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Deffense [45]
2 years ago
8

When Harvey picked up his rental compact car, the odometer read 44,341 miles. When he returned it 4 days later, it read 45,230.

What was his rental on the car if the daily rate was $28.99 and $0.30 per mile with the first 50 miles being free?
Mathematics
2 answers:
Georgia [21]2 years ago
8 0

Answer: daily rate = $28.99

= 28.99*4days= 115.96

Given the 50 miles being free

=0.30*50 = 15.00

= 15-115.96= 100.96

= 100.96

Step-by-step explanation:

dlinn [17]2 years ago
8 0

Answer:

$376.66

Step-by-step explanation:

$28.99 per day for 4 days = $115.96

45,230 miles - 44,341 miles = 889 miles

First 50 miles are free so he owes for 839 miles

The cost per mile is $0.30 so 839($0.30) = $251.70

$251.70 + $115.96 = $376.66

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Which of the following terms correctly describe the object below. Check all that apply
mars1129 [50]

Answer:

Option a,d and e are correct.

Step-by-step explanation:

Pyramid is  the figure in which every base and apex forms triangle.

Polygon is two dimensional figure with straight lines.

Square is a figure in which all four sides are equal.

Solid is a three dimensional figure.

Polyhedron is a three dimensional figure with straight edges and sharp corners.

Prism is a polyhedron with parallel bases.

The given figure is:

Pyramid

Solid

Polyhedron


4 0
2 years ago
Read 2 more answers
The population can be modeled by P(t) = 82.5 − 67.5cos⎡ ⎣(π/6)t ⎤ ⎦, where t is time in months (t = 0 represents January 1) and
Fed [463]

Answer:

The intervals in which the population is less than 20,000 include

(0 ≤ t < 0.74) and (11.26 < t ≤ 12)

Step-by-step explanation:

P(t) = 82.5 - 67.5 cos [(π/6)t]

where

P = population in thousands.

t = time in months.

During a year, in what intervals is the population less than 20,000?

That is, during (0 ≤ t ≤ 12), when is (P < 20)

82.5 - 67.5 cos [(π/6)t] < 20

- 67.5 cos [(π/6)t] < 20 - 82.5

-67.5 cos [(π/6)t] < -62.5

Dividing both sides by (-67.5) changes the inequality sign

cos [(π/6)t] > (62.5/67.5)

Cos [(π/6)t] > 0.9259

Note: cos 22.2° = 0.9259 = cos (0.1233π) or cos 337.8° = cos (1.8767π) = 0.9259

If cos (0.1233π) = 0.9259

Cos [(π/6)t] > cos (0.1233π)

Since (cos θ) is a decreasing function, as θ increases in the first quadrant

(π/6)t < 0.1233π

(t/6) < 0.1233

t < 6×0.1233

t < 0.74 months

If cos (1.8767π) = 0.9259

Cos [(π/6)t] > cos (1.8767π)

cos θ is an increasing function, as θ increases in the 4th quadrant,

[(π/6)t] > 1.8767π (as long as (π/6)t < 2π, that is t ≤ 12)

(t/6) > 1.8767

t > 6 × 1.8767

t > 11.26

Second interval is 11.26 < t ≤ 12.

Hope this Helps!!!

3 0
2 years ago
Abby lists four consecutive multiples of some number. The average of the first two multiples is 28 and the average of the last t
LuckyWell [14K]
I think that would beb2
7 0
2 years ago
Read 2 more answers
A maple syrup company is making a new label for its barrels of syrup. If the barrels are 5 feet tall and have a radius of 2 feet
Elanso [62]

Answer:

(A)62.8 square feet

Step-by-step explanation:

Height of the barrels = 5 feet

Radius of the barrels= 2 feet

\pi=3.14

The barrel is in the shape of a cylinder and the area of the label the company needs is that of the round sides(curved surface area) of the cylinder.

Curved Surface Area of a Cylinder=2\pi rh

=2X3.14X2X5

=62.8 square feet

The company need 62.8 square feet of label.

7 0
2 years ago
Solving for a Confidence Interval: Algebra 2 points possible (graded) In the problems on this page, we will continue building th
baherus [9]

Answer:

Step-by-step explanation:

1) The given inequality is

|\sqrt{n} \frac{(\bar R_n-p)}{\sqrt{p(1-p)} } |

\to n( \bar R _n - p)^2

\to n\bar R +np^2-2nR_np

Arranging the terms  with p² and p, we get

p^2(n+q^2_{\alpha /2)-p(2n \bar R _n+q^2_{\alpha / 2})+n \bar R ^2 _n

Hence, the inequality is of the form

Ap² + Bp + c < 0

2. A quadratic equation of the form

Ap² + Bp + c < 0 with A > 0 looks like

<u>Check the attached image</u>

The region where the values are negative lies between p₁ and p₂ ...

The p₁ < p < p₂

4 0
2 years ago
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