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2 years ago

Answer!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

motikmotik2 years ago

7 0

1-D 2-B 3-A 4-B 5-C 6-B

Sergeu [11.5K]2 years ago

6 0

Answer:

Step-by-step explanation:

1 is d 2 is b 3 is a 4 is b 5 is c and 6 is b

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Please help!! I need to get this done! Im begging you, brainliest and points!

Viefleur [7K]

Answer:

Solution; ( 1, 0 ), and ( - 3, 4 )

Step-by-step explanation:

See procedure below;

First let us make these two functions ( y = -x + 1 , y = x^2 + x - 2 ) equivalent;

- x + 1 = x^2 + x - 2,

-x - x + 1 + 2 - x^2 = 0,

- 2x + 3 - x^2 = 0,

x^2 + 2x - 3 = 0,

Now factor the simplified equation;

x^2 + 2x - 3 = 0,

( x^2 - x ) + ( 3x - 3 ) = 0,

x ( x - 1 ) + 3 ( x - 1 ) = 0,

( x - 1 )( x + 3 ) = 0,

And solve for x;

x - 1 = 0, and x + 3 = 0,

x = 1, and x = - 3

Now substitute this value of x into the two functions as to receive the y values for each x - value;

y = - ( 1 ) + 1, y = 0 for x = 1,

y = ( - 3 )^2 - 3 - 2, y = 9 - 3 - 2, y = 4 for x = - 3,

Solution; ( 1, 0 ), and ( - 3, 4 )

8 0

2 years ago

Ilene who is not yet 21 years old, is two years older than ida

vagabundo [1.1K]

Answer:

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Step-by-step explanation:

0 0

2 years ago

F (x) = x5 − 8x4 + 21x3 − 12x2 − 22x + 20 Three roots of this polynomial function are −1, 1, and 3 + i. Which of the following d

NeTakaya

Answer:

It's D on edge.

5 0

2 years ago

Read 2 more answers

The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Artemon [7]

Answer:

P(X $\geq$ 74) = 0.3707

Step-by-step explanation:

We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Let X = Score of golfers

So, X ~ N( $\mu=73,\sigma^{2}=3^{2}$ )

The z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 73

$\sigma$ = standard deviation = 3

So, the probability that the score of golfer is at least 74 is given by = P(X $\geq$ 74)

P(X $\geq$ 74) = P( $\frac{X-\mu}{\sigma}$ $\geq$ $\frac{74-73}{3}$ ) = P(Z $\geq$ 0.33) = 1 - P(Z < 0.33)

= 1 - 0.62930 = 0.3707

Therefore, the probability that the score of golfer is at least 74 is 0.3707 .

3 0

2 years ago

An airline, believing that 5% of passengers fail to show for flights, overbooks (sells more tickets than there are seats). Suppo

Fittoniya [83]

Answer:

Q1. 13 passengers

Q2. 0.1756 (approx. 0.18)

Step-by-step explanation:

Q1. 267 seats are available on the plane

5% is expected to fail to show up

Hence, no of passengers expected not to show up = 267 * 0.05

= 13.35 (approx 13 passengers)

Q2. See working in the attachment as I had to explain it step by step.

6 0

2 years ago