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podryga [215]
2 years ago
5

Answer!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
motikmotik2 years ago
7 0
1-D 2-B 3-A 4-B 5-C 6-B
Sergeu [11.5K]2 years ago
6 0

Answer:

Step-by-step explanation:

1 is d 2 is  b 3 is a 4 is b 5 is c and 6 is b

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$32 for each hockey stick

Step-by-step explanation:

71+25=96

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Which ordered pair is a solution of the equation?
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Past studies indicate that about 60 percent of the trees in a forested region are classified as softwood. A botanist studying th
alukav5142 [94]

Answer:

1. If it is true that 60 percent of the trees in a forested region are classified as softwood, 0.015 is the probability of obtaining a population proportion greater than 0.6.

Step-by-step explanation:

Hello!

The historical information indicates that 60% of the forest trees are classified as softwood.

A botanist thinks that the proportion might be greater than 60%, so he tested his belief obtaining:

H₀: p = 0.60

H₁: p > 0.60

p-value: 0.015

You need to interpret this p-value. Little reminder:

The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis. It represents the % of size n samples from a population with proportion p=p₀, which will produce a measure that provides evidence as (or stronger) than the current sample that p is not equal to p₀.

The correct answer is:

1. If it is true that 60 percent of the trees in a forested region are classified as softwood, 0.015 is the probability of obtaining a population proportion greater than 0.6.

I hope this helps!

8 0
2 years ago
The pucks used by the National Hockey League for ice hockey must weigh between and ounces. Suppose the weights of pucks produced
Dahasolnce [82]

Answer:

P(5.5

And we can find this probability using the normal standard distribution or excel and we got:

P(-2.769

Step-by-step explanation:

For this case we assume the following complete question: "The pucks used by the National Hockey League for ice hockey must weigh between 5.5 and 6 ounces. Suppose the weights of pucks produced at a factory are normally distributed with a mean of 5.86 ounces and a standard deviation of 0.13ounces. What percentage of the pucks produced at this factory cannot be used by the National Hockey League? Round your answer to two decimal places. "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.86,0.13)  

Where \mu=5.86 and \sigma=0.13

We are interested on this probability

P(5.5

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(5.5

And we can find this probability using the normal standard distribution or excel and we got:

P(-2.769

4 0
2 years ago
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