Answer:
P(X 
74) = 0.3707
Step-by-step explanation:
We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.
Let X = Score of golfers
So, X ~ N(
)
The z score probability distribution is given by;
Z = 
~ N(0,1)
where, 
= population mean = 73
= standard deviation = 3
So, the probability that the score of golfer is at least 74 is given by = P(X 74)
P(X 74) = P( 
) = P(Z 0.33) = 1 - P(Z < 0.33)
= 1 - 0.62930 = 0.3707
Therefore, the probability that the score of golfer is at least 74 is 0.3707 .
Answer:
I think your answer is b and c if not right sorry
Step-by-step explanation:
Hopefully this helps
Part A: f(x)=(5)x+20(alligators) and f(x)=(10)x+25(crocodiles)
Part B: f(x)=(5)(4)+20(alligators) and f(x)=(10)(4)+25(crocodiles)
Alligators: 40 and Crocodiles: 65
Part C: None because the rate of the alligators won't catch up with the rate of crocodiles.
1. To the right of
2. To the left of
3. Below
4. (4.5, 200)
To solve this, you can create an equation. Say the weight of Umbar is x, then Saira weighs x+25. Together they weigh 205. So, you get the equation
x+x+25=205
Then solve for x.
2x+25=205
2x=180
x=90
Then to find Saira's weight, add 25 to Umbar's weight.
90+25=115.
