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vaieri [72.5K]
2 years ago
13

Triangle J K L is shown. The length of L J is 15. Angle K L J is 28 degrees and angle L J K is 110 degrees. Determine the measur

es of all unknown angles and side lengths of △JKL. Round side lengths to the nearest hundredth. m∠K = ° JK ≈ LK ≈

Mathematics
2 answers:
horrorfan [7]2 years ago
6 0

Answer:

<u>∠JKL = 42°</u>

<u>JK = 10.52</u>

<u>LK = 21.07</u>

Step-by-step explanation:

We will use sine rule to find length of unknown sides.

The sin rule is:

\frac{SinA}{a}=\frac{SinB}{b}=\frac{SinC}{c}

First, lets find the unknown angle ∠JKL.

We know sum of all 3 angles in a triangle is 180, so

28 + 110 + ∠JKL = 180

<u>∠JKL = 180 - 28 - 110 = 42°</u>

<u></u>

Now using sine rule, we find JK:

\frac{Sin28}{JK}=\frac{Sin42}{15}\\JKSin42=15Sin28\\JK=\frac{15Sin28}{Sin42}\\JK=10.52

Now using sin rule, we find LK:

\frac{Sin42}{15}=\frac{Sin110}{LK}\\LKSin42=15Sin110\\LK=\frac{15Sin110}{Sin42}\\LK=21.07

kodGreya [7K]2 years ago
4 0

Answer:

Step-by-step explanation:

Determine the measures of all unknown angles and side lengths of △JKL. Round side lengths to the nearest hundredth.

m∠K = 42°  

JK ≈  10.52

LK ≈ 21.07

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Triangle L N M is shown. Angle L N M is a right angle. An altitude is drawn from point N to point O on side L M, forming a right
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Answer:

Therefore the value of k = 6.

Step-by-step explanation:

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LN = m

NM = l

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NO = 4

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Δ LNM ,Δ LON and Δ MON are right Triangle.

To Find :

Om = k = ?

Solution:

In Right angle Triangle By Pythagoras Theorem we have,

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

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LN² = ON² + OL²

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m² = 80   ............( 1 )

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MN² =  ON² + MO²

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LM² = LN² + MN²

(8 + k)² = m² + l² .................( 3 )

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64 + 16k+k^{2} = 80+ 16 +k^{2} \\\\16k=96\\\\\therefore k=\frac{96}{16} \\\\\therefore k=6

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8. In how many ways can a committee of four be selected from eight men and seven women if Miss Jones refuses to serve on the sam
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If the exclusion of Miss Jones and Mr Smith serving together was not present, the are 15C4 = 1365 ways of selecting the committee.
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b) with 2 men and another woman
c) with 1 man and 2 other women
d) with 3 other women.
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