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Yuliya22 [10]
2 years ago
12

Jere Gundersen receives $900 per month from Social Security and his wife, Vardah, receives 60 percent of the amount Jere does. I

f Jere and Vardah have a retirement income of $1,800 per month, how much must Jere receive from his pension?
Mathematics
2 answers:
frosja888 [35]2 years ago
7 0
Jere recives $900 and His wife recives 60% that will be 60/100*900=540 then $900+$540=1440.
Pension amount=1800-1440=360.
LenaWriter [7]2 years ago
5 0

Answer:

360

Step-by-step explanation:

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A police car's siren operates at a frequency of 2,000 Hz. What frequency would a stationary listener observe if the police car i
SpyIntel [72]

we can use formula

f_L=f_s(\frac{v_a-v_p}{v_a+v_p} )

where

fL is listener frequency

fs is siren frequency

va is the speed of sound in air

vs is police car speed

so, we have

f_s=2000Hz

v_a=345m/s

v_p=65mph

now, we can change it into m/s

v_p=65*\frac{1609}{3600}m/s

v_p=29.05139m/s

now, we can plug it

f_L=2000(\frac{345-29.05139}{345+29.05139} )

f_L=1689.33263Hz..............Answer

3 0
2 years ago
If the tangent of an angle of a right angled triangle is 0.8 , then it's longest side is
Blababa [14]

Step-by-step explanation:

  • Assume non-hypotenuse sides are 4 and 5, so tan =4/5=0.8 . Then hypotenuse is sqrt(16+25) = sqrt(41) So sides are 4,5,sqrt (41).
8 0
2 years ago
A textbook has 500 pages on which typographical errors could occur. Suppose that there are exactly 10 such errors randomly locat
DiKsa [7]

Answer:

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that the selection of the random pages will contain at least two errors is 0.2644

Step-by-step explanation:

From the information given:

Let q represent the no of typographical errors.

Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let \mu be the random variable that follows a Poisson distribution, then mean \mu = \dfrac{10}{500}= 0.02

and the mean that the random selection of 50 pages will contain no error is \lambda = 50 \times 0.02 =1

∴

Pr(q= 0) = \dfrac{e^{-1} (1)^0}{0!}

Pr(q =0) = 0.368

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that 50 randomly page contains at least 2 errors is computed as follows:

P(X ≥ 2) = 1 - P( X < 2)

P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )]    since it is less than 2

P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]

P(X \geq 2) = 1 - [0.3678 +0.3678]

P(X \geq 2) = 1 -0.7356

P(X ≥ 2) = 0.2644

The probability that the selection of the random pages will contain at least two errors is 0.2644

6 0
2 years ago
they paid $13 for each pepperoni pizza and $11for each plain pizza the club bought total of 18 pizzas for the party and paint a
jeka94

Complete question;

A booster club paid for pizzas for an  end of season party. They paid $13  for each pepperoni pizza and $11 for  each plain pizza. The club bought a

total of 18 pizzas for the party and  paid a total of $212.

Drag and drop the numbers to the  boxes to create an equation which  models this situation if x = the  number of pepperoni pizzas and y =  the number of plain pizzas bought.

Answer:

13x + 11y = 212

Step-by-step explanation:

They bought 2 different recipe of pizza. The first is the pepperoni pizza and the second kind is the plain pizza. The pepperoni pizza cost $13 each while the  plain Pizza cost $11 each. The total number of pizza bought is 18 in number.

The total cost of the pizza is also $212.

number of pizza bought = 18

total cost of pizza = $212

x = the  number of pepperoni pizzas

y =  the number of plain pizzas

The number of pepperoni pizzas multiply by the cost for each will give the cost of the pepperoni pizzas. This same method is applied to get the cost of the plain pizzas.

Therefore, adding the individual cost of the kinds of pizza will give the total cost of the pizzas.

13x + 11y = 212

4 0
2 years ago
Which of the following is a zero of the function f(x) = x3 - x2 - 21x + 45.
marin [14]
The zeros are 3 and -5. Hope this helps!
5 0
2 years ago
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