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hoa [83]
2 years ago
9

Bailey’s Cakes and Pastries baked a three-tiered cake for a wedding. The bottom tier is a rectangular prism that is 18 centimete

rs long, 12 centimeters wide, and 8 centimeters tall. The middle tier is a rectangular prism that is 12 centimeters long, 8 centimeters wide, and 6 centimeters tall. The top tier is a cube with edges of 4 centimeters each. What is the volume of each tier and of the entire cake?
Mathematics
1 answer:
vodomira [7]2 years ago
7 0
Tier one=1728 cm²
Tier two= 576cm²
Tier three=64cm²
Entire cake=2368cm²

Plz give branliest :)
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A company buys paper at the rate of $10.50 per package for the first 10 packages, $8.50 per package for the next 10 packages, an
dexar [7]

Answer:

25?

Step-by-step explanation:


7 0
2 years ago
Read 2 more answers
Suppose you have a litter of mice which consists of 8 males and 4 females. If you randomly grab two of them, what is the probabi
tiny-mole [99]

Answer:

The probability that they are both male is 0.424 (3 d.p.)

Step-by-step explanation:

The first step is to find the probability of the first selection being male. This is calculated as number of male mice divided by total number of mice in the litter

Prob (1st male) = 8 ÷ 12 = 0.667

Next is to find the probability of the second selection also being male. Note that the question states that the first mice was selected without replacement. This means the first mouse taken results in a reduction in both the number of male mice and total number of mice in the litter.

Prob (2nd male) = (8 - 1) ÷ (12 - 1) = 7/11 = 0.636

Therefore,

Prob (1st male & 2nd male) = 0.667 × 0.636 = 0.424

5 0
2 years ago
Emma borrowed $300 to repair her car. the finance (interest) charge on the loan was $20, and the term on the loan was 14 days. w
Murrr4er [49]
Given:
loan amount = 300
finance charge = 20
term = 14 days.

To solve for APR.
<span>1. Divide the finance charge by the loan amount.
20/300 = 0.0667

2. Multiply the result by 365. 
0.0667 x 365 = 24.35

3. Divide the result by the term of the loan.
24.35/14 = 1.74 (APR in decimal format)
<span>
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7 0
2 years ago
According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 15x11 – 6x8 + x3 – 4x + 3?
scoundrel [369]

we have

f(x) = 15x^{11} -6x^{8} + x^{3} - 4x + 3

we know that

<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms

x=\frac{p}{q}

p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.

So

in this problem

the constant term is equal to 3

and the first monomial is equal to 15x^{11} -----> coefficient is 15

So

possible values of p are 1, and\ 3

possible values of q are 1, 3, 5, and\ 15

therefore

<u>the answer is</u>

The all potential rational roots of f(x) are

(+/-)\frac{1}{15},(+/-)\frac{1}{5},(+/-)\frac{1}{3},(+/-)\frac{3}{5},(+/-)1,(+/-)3


3 0
2 years ago
Read 2 more answers
Evaluate. 58−(14)2=58-142= ________
nasty-shy [4]

For this case we have the following expression:

58- (14) ^ 2

The first step is to solve the quadratic term.

We have then:

58- (14) ^ 2 = 58-196

Then, the second step is to subtract both resulting numbers:

58- (14) ^ 2 = -138

We observe that the result obtained is a negative number.

Answer:

The result of the expression is given by:

58- (14) ^ 2 = -138

7 0
2 years ago
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