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notsponge [240]

2 years ago

7

An airplane flew at an average rate of 600 miles per hour from Tokyo to Seattle. Because of a strong headwind, the average rate

of the return trip was only 480 mph. The round trip took 18 hours. Which equation can be used to determine the time for each leg? 600t = 480t 600t = 18 – t 600t = 480 – t 600t = 480(18 – t)

2 answers:

Dvinal [7]2 years ago

5 0

600t = 480(18 – t) should be it

larisa [96]2 years ago

3 0

Answer:

Option D. 600t = 480( 18-t )

Step-by-step explanation:

An airplane flew at an average rate of 600 miles per hour fro Tokyo to Seattle.

Let the airplane travels for t hours so distance covered by the airplane will be = speed × time

= 600t miles

Similarly, average speed in return trip was 480 mile/hour. So distance covered in return trip = speed × time

= 480 ( 18-t ) [ since time taken by plane in round trip was 18. So time taken in return trip will be ( 18-t) ]

Therefore, distance traveled in one trip = distance covered in return trip

600t = 480( 18-t )

Option D is the answer.

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Answer:

1) A is a cat; B is a dog; C is a cat; D is a dog; E is a dog; F is a cat

2) A lives with B in a yellow house; C lives with D in a blue house; E lives with F in a red house.

Step-by-step explanation:

Step 1: First we identify the animals as cats or dogs

A is a cat

B is a Dog

Since B can live with C, C is a cat

Since D can live with A, D is a dog

F is a cat since it can live with D

E is therefore, a dog

Step 2: We then identify the house each two animals live in pairs of a cat and a dog

D lives in a blue house

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2 years ago

Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =

FromTheMoon [43]

Answer:

Here is the question attached with.

$m\angle CEA =90 \ (deg)$

$m\angle BEF=135\ (deg)$

$\angle CEF$ is a straight line.

$\angle AEF$ is a right angled triangle.

Options $1,4,5,6$ are correct answers.

Step-by-step explanation:

⇒As $\ ray\ AE$ is ⊥ $FEC$ so it will forms right angled triangle then $m\angle CEA =90\ (deg)$ .

⇒Measure of $\angle BEF =135\ (deg)$ as $\angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg)$ as $\angle AEB$ is the bisector of $\angle AEC$ ,meaning that $\angle AEB$ is half of $\angle AEC$ so $\angle AEB = 45\ (deg)$ .

⇒ $\angle CEF$ is a straight line as the angles measure over it is $180\ (deg)$ .

⇒Measure of $\angle AEF = 90\ (deg)$ from linear pair concept.

As $\angle CEA + \angle AEF = 180\ (deg)$ ,plugging the values of $m\angle CEA =90\ (deg)$ we have $\angle AEF = 90\ (deg)$ .

The other two options are false as:

$m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225$

it is exceeding $180\ (deg)$ whereas $\angle CEF$ is a

straight line.

And $m\angle CEB=2(m\angle CEA)$ is not true.

As $\angle CEA = 90\ (deg)$ and $\angle CEB=45\ (deg)$

So we have total $4$ answers.

The correct options are $1,4,5,6$ .

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