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2 years ago

Complete the synthetic division problem below. What is the quotient in polynomial form?

Mathematics

2 answers:

Vladimir [108]2 years ago

4 0

Answer:

A.2x²- 2x+2

Step-by-step explanation:apex

mr Goodwill [35]2 years ago

3 0

A; you need to bring down the first term, 2, multiply it by -2, resulting in -4. Add -4 to 2 to get -2. Multiply -2 and get a product of 4, and add that to the third term, -4. That would give you 2, that would then be multiplied by -2 to get -4 and when added to 4, would give you a remainder of 0.

The quotient coefficients would be 2, -2, and 2, which becomes 2x² -2x + 2.

Hope this helped :)

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Brody had his computer repaired at Store A. His bill was:

tekilochka [14]

Answer:

$190.80 gratuity tip.

Step-by-step explanation:

Adding up the initial cost and tax, it adds up to $1,272. Subtracting 85% from the total is $190.80.

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2 years ago

10. If PQRS is a parallelogram, then P - R is:<br>(a) 20<br>(b) 30<br>(c) 90<br>(d) 0

statuscvo [17]

Answer:

d) 0

Step-by-step explanation:

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2 years ago

Emerson purchased a game that was on sale for 18% off. The sales tax in his county is 8%. Let y represent the original price of

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(y - 0.18y) * 1.08
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2 years ago

Read 2 more answers

Solve for x in the equation ? 2x^2 +3 x-7 =x^2 +5x +39

otez555 [7]

Answer:

1 ± √47

Step-by-step explanation:

Combine like terms in 2x^2 +3 x-7 =x^2 +5x +39:

2x^2 - x^2 = x^2 (first term);

3x - 5x = -2x (second term);

-7 - 39 = -46 (third term)

Then we have, all on the left side, x^2 - 2x - 46, which is a quadratic equation. Here the coefficients are a = 1, b = -2 and c = -46.

Then the discriminant, b^2 - 4ac, is:

(-2)^2 - 4(1)(-46) = 4 + 184.

The roots are:

-(-2) ±√188 2 ± √4√47

------------------- = -------------------

2 2

= 1 ± √47 (last of the answer choices)

x = ------------------

3 0

2 years ago

The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillat

Greeley [361]

Answer:

1) $L \propto T^2$

Using the condition given:

$2.205 m = K (3)^2$

$K = 0.245 \approx \frac{g}{4\pi^2}$

So then if we want to create an equation we need to do this:

$L = K T^2$

With K a constant. For this case the period of a pendulumn is given by this general expression:

$T = 2\pi \sqrt{\frac{L}{g}}$

Where L is the length in m and g the gravity $g = 9.8 \frac{m}{s^2}$ .

2) $T = 2\pi \sqrt{\frac{L}{g}}$

If we square both sides of the equation we got:

$T^2 = 4 \pi^2 \frac{L}{g}$

And solving for L we got:

$L = \frac{g T^2}{4 \pi^2}$

Replacing we got:

$L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m$

3) $T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s$

Step-by-step explanation:

Part 1

For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.

$L \propto T^2$

Using the condition given:

$2.205 m = K (3)^2$

$K = 0.245 \approx \frac{g}{4\pi^2}$

So then if we want to create an equation we need to do this:

$L = K T^2$

With K a constant. For this case the period of a pendulumn is given by this general expression:

$T = 2\pi \sqrt{\frac{L}{g}}$

Where L is the length in m and g the gravity $g = 9.8 \frac{m}{s^2}$ .

Part 2

For this case using the function in part a we got:

$T = 2\pi \sqrt{\frac{L}{g}}$

If we square both sides of the equation we got:

$T^2 = 4 \pi^2 \frac{L}{g}$

And solving for L we got:

$L = \frac{g T^2}{4 \pi^2}$

Replacing we got:

$L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m$

Part 3

For this case using the function in part a we got:

$T = 2\pi \sqrt{\frac{L}{g}}$

Replacing we got:

$T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s$

8 0

2 years ago