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Evgesh-ka [11]
2 years ago
8

When dealing with the number of occurrences of an event over a specified interval of time or space and when the occurrence or no

noccurrence in any interval is independent of the occurrence or nonoccurrence in any other interval, the appropriate probability distribution is a _____.
Mathematics
1 answer:
jeyben [28]2 years ago
7 0

Answer:

POISSON DISTRIBUTION

Step-by-step explanation:

When dealing with the number of occurrences of an event over a specified interval of time or space, the poisson distribution is often useful.

Poisson distribution is applicable if:

The probability of the occurrence of the event is the same for any two intervals of equal length.

The occurrence or nonoccurrence of the event in any interval is independent of the occurrence or nonoccurrence in any other interval.

The probability that two or more events will occur in an interval approaches zero as the interval becomes smaller.

Therefore, the appropriate probability distribution is POISSON PROBABILITY DISTRIBUTION.

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you have piano lessons every 7 days and tuba lessons every 3 days. Today you have both lessons. Not counting today or the day wh
Neporo4naja [7]

You will have 2 piano lessons and 6 tuba lessons


4 0
2 years ago
A scale model of a house is 1 ft. long. The actual house is 50 ft long. In the model, the window is 1 1/5 in. high. How many fee
stich3 [128]
First, identify the ratio:
1:50 (1 foot on the model is 50 feet on the house)
to find the actual height of the window multiply 1 1/5 by 50
\frac{6}{5}*\frac{50}{1}=\frac{300}{5}
300/5 simplifies into 60
the height of the real window is 60 feet 

6 0
2 years ago
Find an equation of the line containing the centers of the two circles whose equations are given below.
Anna35 [415]

Answer:

<h2><em>3y+x = -5</em></h2>

Step-by-step explanation:

The general equation of a circle is expressed as x²+y²+2gx+2fy+c = 0 with centre at C (-g, -f).

Given the equation of the circles x²+y²−2x+4y+1  =0  and x²+y²+4x+2y+4  =0, to  get the centre of both circles,<em> we will compare both equations with the general form of the equation above as shown;</em>

For the circle with equation x²+y²−2x+4y+1  =0:

2gx = -2x

2g = -2

Divide both sides by 2:

2g/2 = -2/2

g = -1

Also, 2fy = 4y

2f = 4

f = 2

The centre of the circle is (-(-1), -2) = (1, -2)

For the circle with equation x²+y²+4x+2y+4  =0:

2gx = 4x

2g = 4

Divide both sides by 2:

2g/2 = 4/2

g = 2

Also, 2fy = 2y

2f = 2

f = 1

The centre of the circle is (-2, -1)

Next is to find the equation of a line containing the two centres (1, -2) and (-2.-1).

The standard equation of a line is expressed as y = mx+c where;

m is the slope

c is the intercept

Slope m = Δy/Δx = y₂-y₁/x₂-x₁

from both centres, x₁= 1, y₁= -2, x₂ = -2 and y₂ = -1

m = -1-(-2)/-2-1

m = -1+2/-3

m = -1/3

The slope of the line is -1/3

To get the intercept c, we will substitute any of the points and the slope into the equation of the line above.

Substituting the point (-2, -1) and slope of -1/3 into the equation y = mx+c

-1 = -1/3(-2)+c

-1 = 2/3+c

c = -1-2/3

c = -5/3

Finally, we will substitute m = -1/3 and c = 05/3 into the equation y = mx+c.

y = -1/3 x + (-5/3)

y = -x/3-5/3

Multiply through by 3

3y = -x-5

3y+x = -5

<em>Hence the equation of the line containing the centers of the two circles is 3y+x = -5</em>

5 0
2 years ago
19. Bella is putting down patches of sod
Fofino [41]

Answer:

The dimensions of the two different rectangular regions are;

1st Arrangement:

W = 4 yards and L = 5 yards or W = 5 yards and L = 4 yards

2nd Arrangement:

W = 2 yards and L = 10 yards or W = 10 yards and L = 2 yards

The perimeter of the two different rectangular regions are;

1st Arrangement:

P₁ = 18 yards

2nd Arrangement:

P₂ = 24 yards

Step-by-step explanation:

Bella is putting down patches of sod to start a new lawn.

She has 20 square yards of sod.

We are asked to provide the dimensions of two different rectangular regions that she can cover with the sod.

Recall that a rectangle has an area given by

Area = W*L

Where W is the width of the rectangle and and L is the length of the rectangle.

Since Bella has 20 square yards of sod,

20 = W*L

There are more than two such possible rectangular arrangements.

Out of them, two different possible arrangements are;

1st Arrangement:

20 = (4)*(5) = (5)*(4)

Width is 4 yards and length is 5 yards or width is 5 yards and length is 4 yards

2nd Arrangement:

20 = (2)*(10) = (10)*(2)

Width is 2 yards and length is 10 yards or width is 10 yards and length is 2 yards

Therefore, the dimensions of two  different rectangular regions are;

1st Arrangement:

W = 4 yards and L = 5 yards or W = 5 yards and L = 4 yards

2nd Arrangement:

W = 2 yards and L = 10 yards or W = 10 yards and L = 2 yards

What is the perimeter of each region?

The perimeter of a rectangular shape is given by

P = 2(W + L)

Where W is the width of the rectangle and and L is the length of the rectangle.

The perimeter of the 1st arrangement is

P₁ = 2(4 + 5)

P₁ = 2(9)

P₁ = 18 yards

The perimeter of the 2nd arrangement is

P₂ = 2(2 + 10)

P₂ = 2(12)

P₂ = 24 yards

So the perimeter of the 1st arrangement is 18 yards and the perimeter of the 2nd arrangement is 24 yards.

Note:

Another possible arrangement is,

20 = (1)*(20) = (20)*(1)

Width is 1 yard and length is 20 yards or width is 20 yards and length is 1 yard.

3 0
1 year ago
5(0.04y-0.08) &gt;3(0.2y-0.05-0.4y)
MAXImum [283]

0.08(y + -1) + 0.12y = 0.14 + -0.05(10)

Reorder the terms:

0.08(-1 + y) + 0.12y = 0.14 + -0.05(10)

(-1 * 0.08 + y * 0.08) + 0.12y = 0.14 + -0.05(10)

(-0.08 + 0.08y) + 0.12y = 0.14 + -0.05(10)

Combine like terms: 0.08y + 0.12y = 0.2y

-0.08 + 0.2y = 0.14 + -0.05(10)

Multiply -0.05 * 10

-0.08 + 0.2y = 0.14 + -0.5

Combine like terms: 0.14 + -0.5 = -0.36

-0.08 + 0.2y = -0.36

Solving

-0.08 + 0.2y = -0.36

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '0.08' to each side of the equation.

-0.08 + 0.08 + 0.2y = -0.36 + 0.08

Combine like terms: -0.08 + 0.08 = 0.00

0.00 + 0.2y = -0.36 + 0.08

0.2y = -0.36 + 0.08

Combine like terms: -0.36 + 0.08 = -0.28

0.2y = -0.28

Divide each side by '0.2'.

y = -1.4

Simplifying

y = -1.4

3 0
2 years ago
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