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1 year ago

5

Mario invested $6,000 in an account that pays 5% annual interest compounded annually. Using the formula A = P(1 + r)t, what is t

he approximate value of the account after 2.5 years?
a. $6,075
b. $6,118
c. $6,456
d. $6,778

1 answer:

jok3333 [9.3K]1 year ago

6 0

Given:
Principal = 6,000
interest rate = 5%
term = 2.5 years

A = P (1+r)^t
A = 6,000 (1 + 0.05)².⁵
A = 6,000 (1.05)².⁵
A = 6,000 (1.1297)
A = 6,778.20 Choice D.

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Step-by-step explanation:

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1 year ago

Let e1= 1 0 and e2= 0 1 , y1= 4 5 , and y2= −2 7 , and let T: ℝ2→ℝ2 be a linear transformation that maps e1 into y1 and maps

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Answer:

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Step-by-step explanation:

We know that $T:$ $IR^{2}$ → $IR^{2}$ is a linear transformation that maps $e_{1}$ into $y_{1}$ ⇒

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And also maps $e_{2}$ into $y_{2}$ ⇒

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We know that exists a matrix A from $IR^{2x2}$ (because of how T was defined) such that :

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We can find the matrix A by applying T to a base of the domain ( $IR^{2}$ ).

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Being $B_{IR^{2}}$ the cannonic base of $IR^{2}$

The following step is to put the images from the vectors of the base into the columns of the new matrix A :

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Writing the matrix A :

$A=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]$

Now with the matrix A we can find the image of $\left[\begin{array}{c}4&-4\\\end{array}\right]$ such as :

$T(x)=Ax$ ⇒

$T(\left[\begin{array}{c}4&-4\end{array}\right])=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]\left[\begin{array}{c}4&-4\end{array}\right]=\left[\begin{array}{c}24&-8\end{array}\right]$

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Answer:

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Answer:

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