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xeze [42]
2 years ago
15

Find the area of the trapezoidal cross-section of the irrigation canal shown below. Your answer will be in terms of h, w, and θ.

Mathematics
1 answer:
Setler [38]2 years ago
5 0
The answer is :h^2/tanθ+wh
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Leilah has not yet
Ivenika [448]

Answer:

40 * x - 600 = 0

Step-by-step explanation:

The first thing is to identify the variable (x) of the equation and they will be the number of days that Leilah will take to read her flashcards. Now if you need to study 600 out of 2400, it is because you have read 1800. Therefore we have to:

2400 - 1800 = 40 * x

rearranging

40 * x - 600 = 0

The above would be the equation of the situation

6 0
2 years ago
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Find the third degree polynomial function that has an output of 1,025 when x=5, and has zeros −20 and −4i.
Mumz [18]

Answer:

im not sure

Step-by-step explanation:

8 0
2 years ago
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A log splitter uses a pump with hydraulic oil to push a piston, attached to which is a chisel. The pump can generate a pressure
faust18 [17]

we are given

The pump can generate a pressure of 2.3x107 pa

so,

p=2.3*10^7

a radius of 0.041 m

so,

r=0.041m

a stroke lasting 29 s, the piston moves 0.57 m

so,

h=0.57m

t=29s

Firstly, we will find area

A=\pi r^2

A=\pi (0.041)^2

A=0.00528

now, we can use power formula

P=\frac{W}{t}

F=pA

W=Fh

so, W=pAh

we can plug it

P=\frac{p*A*h}{t}

now, we can plug values

P=\frac{2.3*10^7*0.00528*0.57}{29}

now, we can simplify it

Power=2386.92414 watt.........Answer

6 0
2 years ago
A log is 16m long, correct to the nearest metre. It has to be cut into fence posts which must be 70cm long, correct to the neare
dmitriy555 [2]

Answer:

25 posts

Step-by-step explanation:

So the number of fence post would be the total length of the log divided by the length of each post. As the log is 16m and is corrected to the nearest metre, it could possibly be 16.499m. As for the post that is 70 cm long and corrected to the nearest 10cm, it may as well be 65 cm (or 0.65m) each post

So the max number of fence point once can possibly cut from the log would be

16.499 / 0.65 = 25 posts

5 0
2 years ago
Given: ΔABC, AC = BC, AB = 3 CD⊥ AB, CD = 3 Find: AC
viva [34]

Answer:

3\sqrt{5}/2

Step-by-step explanation:

As given, AC = BC, its an isosceles triangle.

Now, CD is perpendicular to AB, therefore AD = DB = 0.5AB = 3/2

Now take triangle ACD,

using Pythagoras theorem,

AC = \sqrt{AD^{2} + CD^{2}   }

AC = 3\sqrt{5}/2

:-)

4 0
2 years ago
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