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2 years ago

The change in the value of a stock is represented by the rational number -5.90 describe in words what this means

Mathematics

1 answer:

xxMikexx [17]2 years ago

3 0

We are given : A stock is represented by -5.90.

The given number is a negative number.

Note: When a stock is given by a negative number, it represents the decrease in stock and when a stock is given by a positive number, it represents the increase in stock.

As we are given number is a negative number, we can just say that

" The stock value is being decrease by 5.90".

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Answer:

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Step-by-step explanation:

We are given that

The mass of a colony of bacteria (in (grams) is given by

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Where t=Time(in days)

Differentiate w.r.t t

$P'(t)=5(\frac{1}{1+\frac{t^2}{4}}\times \frac{1}{2})$

By using the formula $\frac{d(tan^{-1}(x)}{dx}=\frac{1}{1+x^2}$

$P'(t)=\frac{5}{2}(\frac{4}{4+t^2})$

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We are given P(t)=6

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$5tan^{-1}(\frac{t}{2})=6-2=4$

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$\frac{t}{2}=tan(\frac{4}{5})$

$t=2tan(\frac{4}{5})$

Substitute the value of t

$P'(2tan\frac{4}{5})=\frac{10}{4+4tan^2(\frac{4}{5})}$

$P'(2tan\frac{4}{5})=\frac{10}{4}\times \frac{1}{1+tan^2(\frac{4}{5})}$

We know that $1+tan^2\theta=sec^2\theta$

Using the formula

$P'(2tan(\frac{4}{5})=\frac{5}{2}\times \frac{1}{sec^2(\frac{4}{5})}$

$P'(2tan\frac{4}{5})=\frac{5}{2}\times cos^2(\frac{4}{5})$

By using $cos^2x=\frac{1}{sec^2x}$

$P'(2tan\frac{4}{5})=\frac{5}{2}\times (0.696)^2=1.21$ g/day

Hence,the instantaneous rate of change of the mass of the colony=1.21g/day

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Answer:

<em>The ferry can travel $\frac{7}{18}$ of the distance between the two ports in one hour.</em>

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Suppose, the ferry traveled $x$ of the distance between the two ports in one hour.

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Answer:

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Step-by-step explanation:

Let x be the number.

As per the statement:

At a pizzeria, the ratio of pizzas topped with meat to pizzas topped with vegetables was 4:3 on Saturday.

The ratio of pizza topped with meat to pizzas topped with vegetables = 4 : 3

then;

the number of pizza topped with meat = 4x

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