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andreyandreev [35.5K]
1 year ago
15

Identify whether the series summation of 12 open parentheses 3 over 5 close parentheses to the I minus 1 power from 1 to infinit

y is a convergent or divergent geometric series and find the sum, if possible.
Mathematics
1 answer:
Finger [1]1 year ago
3 0
∑ from 1 to infinity of 12(3/5)^(i - 1)
Since the common ratio is less than 1, the series is convegent. [i.e. 3/5 < 1]

Sum to infinity of a geometric series is given by a/(1 - r); where a is the first term, and r is the common ratio.

Sum = 12/(1 - 3/5) = 12/(2/5) = 30.
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Liz and Andy make money selling jewelry at a local fair. Liz and Andy both sell necklaces for $8 each. Andy also sells bracelets
Gelneren [198K]

Equation for Liz:

L = 8n

Equation for Andy:

A = 8n + 35

Step-by-step explanation:

Let the no. of necklace be 'n'

Cost per necklace= $8

Equation for Liz:

L = 8n

Because Liz sells only necklace for $8 each

Equation for Andy:

A = 8n + 35

Because Andy sells each necklace for $8 and she sold the bracelets for $35

7 0
1 year ago
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Use the drop-down menus to complete the proof. Given that w ∥ x and y is a transversal, we know that ∠1 ≅∠5 by the . Therefore,
ololo11 [35]

Answer:

From the graph attached, we know that \angle 1 \cong \angle 5 by the corresponding angle theorem, this theorem is about all angles that derive form the intersection of one transversal line with a pair of parallels. Specifically, corresponding angles are those which are placed at the same side of the transversal, one interior to parallels, one exterior to parallels, like \angle 1 and \angle 5.

We also know that, by definition of linear pair postulate, \angle 3 and \angle 1 are linear pair. Linear pair postulate is a math concept that defines two angles that are adjacent and for a straight angle, which is equal to 180°.

They are supplementary by the definition of supplementary angles. This definition states that angles which sum 180° are supplementary, and we found that \angle 3 and \angle 1 together are 180°, because they are on a straight angle. That is, m \angle 3 + m \angle 1 = 180\°

If we substitute \angle 5 for \angle 1, we have m \angle 3 + m \angle 5 = 180\°, which means that \angle 3 and \angle 5 are also supplementary by definition.

4 0
1 year ago
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The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section
LUCKY_DIMON [66]

Answer:

y2 = C1xe^(4x)

Step-by-step explanation:

Given that y1 = e^(4x) is a solution to the differential equation

y'' - 8y' + 16y = 0

We want to find the second solution y2 of the equation using the method of reduction of order.

Let

y2 = uy1

Because y2 is a solution to the differential equation, it satisfies

y2'' - 8y2' + 16y2 = 0

y2 = ue^(4x)

y2' = u'e^(4x) + 4ue^(4x)

y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)

= u''e^(4x) + 8u'e^(4x) + 16ue^(4x)

Using these,

y2'' - 8y2' + 16y2 =

[u''e^(4x) + 8u'e^(4x) + 16ue^(4x)] - 8[u'e^(4x) + 4ue^(4x)] + 16ue^(4x) = 0

u''e^(4x) = 0

Let w = u', then w' = u''

w'e^(4x) = 0

w' = 0

Integrating this, we have

w = C1

But w = u'

u' = C1

Integrating again, we have

u = C1x

But y2 = ue^(4x)

y2 = C1xe^(4x)

And this is the second solution

5 0
2 years ago
You need at least $485 to go on a trip to New York City. You already have $100 saved for the trip. You decide to save an additio
elena-14-01-66 [18.8K]
Remark
The entire trip costs 485 dollars. She has a hundred, and you are looking for the number of weeks needed to save for the trip.

Step one
Set up the basic equation.
35w + 100 ≥ 485

Step two
solve
35w + 100 ≥ 485        Subtract 100 from both sides.
35W ≥ 485 - 100         
35W ≥ 385 Divide by 35
W ≥ 385 / 35
W ≥ 11 weeks.

Since we don't have choices, we can't eliminate those that are wrong.

If I had to guess I would say it was something that looked like
35W + 100 ≥ 485

3 0
2 years ago
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The car you just bought keeps breaking down. The parts you need to buy cost $408.97. Your mechanic also charges $53 per hour for
DiKsa [7]
C. repair charge = 53 * hours of labor + 408.97
7 0
2 years ago
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