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DENIUS [597]
1 year ago
8

A landscaping company is delivering crushed stone to a construction site .The Table shows the total weight in pounds W, of n loa

ds of crushed stone. Which equation could represent the total weight, in pounds ,for n loads of crushed stone?
A.600/n
B.W=6,000-2,000n
C.W=2,000n
D.W=n+2,000

Mathematics
1 answer:
irina1246 [14]1 year ago
3 0

Answer:

Option (C)

Step-by-step explanation:

From the given table,

Dependent variable is the weight of each load and independent variable is number of loads of crushed stones.

Let the equation that represents the total weight is,

W = mn + b

Where 'm' = slope of the line

b = y-intercept

n = number of loads

Since graph starts from the origin (0, 0), y - intercept 'b' will be 0.

Two points lying on the line are (0, 0) and (1, 2000)

Slope of the line 'm' = \frac{y_2-y_1}{x_2-x_1}

                                  = \frac{2000-0}{1-0}

                                  =2000

Therefore, equation will be,

W = 2000n

Option (C) will be the answer.

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Orin solved an equation and justified his steps as shown in the table.
sergij07 [2.7K]

Answer:

Step-by-step explanation:

Given the equation as

\frac{3x}{5} -3=12

apply multiplication property of equality where you multiply every term by 5

\frac{3x}{5}*5 -3*5=12*5

3x-15=60------------------apply addition property of equality

3x-15+15=60+15

3x=75--------------------------appy division property of equality by dividing both sides by 3

3x/3=75/3

x=25

6 0
1 year ago
If a plant grows 1/4 cm every day for 21 days, what is the total<br> amount of growth?
Naddika [18.5K]
I think it’s 5.25 cm but you might want to double check.
5 0
1 year ago
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What is the common difference between the elements of the arithmetic sequence below?
fredd [130]
All numbers in each number add up to 9, i dont know if you understand me, 
for example:
1+8=9
2+2+5=9
2+7=9
.....

3 0
1 year ago
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at the game, mrs. burns spent $45 for 4 soft pretzels, 3 bags of peanuts, and 8 bottles of water for snacks for the family. a bo
Irina18 [472]

Answer:

<u>The correct statements are A. The cost of a bottle of water is p – 0.75, C. The cost of a soft pretzel is $3.25. and D. The cost of a bag of peanuts is $4.00.</u>

Step-by-step explanation:

1. This is the information given to solve the case:

Amount spent by Mrs. Burns at the game = US$ 45

Detailed purchase done by Mrs. Burns = 4 soft pretzels, 3 bags of peanuts and 8 bottles of water.

Price of soft pretzel = p

Price of bag of peanuts = p + US$ 0.75

Price of bottle of water = p - US$ 0.75

2. This is the equation for solving the case:

4p + 3(p + 0.75) + 8(p - 0.75) = 45

4p + 3p + 2.25 + 8p - 6 = 45

4p + 3p + 8p = 45 + 6 - 2.25

15p = 48.75

p = 3.25

<u>The price of a soft pretzel is US$ 3.25, of a bag of peanuts is US$ 4 (3.25 + 0.75) and of a bottle of water is US$ 2.50 (3.25 - 0.75).</u>

3. Now, we have all the information necessary to analyze the statements.

A. The cost of a bottle of water is p – 0.75.<u> It's correct</u>.

B. The equation that represents this scenario is (p – 0.75) + (p – 0.75) + p = 45. <u>It's false.</u>

C. The cost of a soft pretzel is $3.25. <u>It's correct.</u>

D. The cost of a bag of peanuts is $4.00.<u> It's correct.</u>

E. The cost of 8 bottles of water is $26.00. <u>It's false. (8 * 2.50 = 20)</u>

<u>The correct statements are A. The cost of a bottle of water is p – 0.75, C. The cost of a soft pretzel is $3.25. and D. The cost of a bag of peanuts is $4.00.</u>

5 0
1 year ago
Read 2 more answers
A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)
Maksim231197 [3]

Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

b

The sample proportion is  \r p =  0.09

c

The critical value is  Z_{\frac{\alpha }{2} } =  1.96

d

 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

        \alpha  =  5\%

        \alpha  =  0.05

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

7 0
1 year ago
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