A landscaping company is delivering crushed stone to a construction site .The Table shows the total weight in pounds W, of n loa
ds of crushed stone. Which equation could represent the total weight, in pounds ,for n loads of crushed stone?
A.600/n
B.W=6,000-2,000n
C.W=2,000n
D.W=n+2,000
A.600/n
B.W=6,000-2,000n
C.W=2,000n
D.W=n+2,000
1 answer:
Answer:
Option (C)
Step-by-step explanation:
From the given table,
Dependent variable is the weight of each load and independent variable is number of loads of crushed stones.
Let the equation that represents the total weight is,
W = mn + b
Where 'm' = slope of the line
b = y-intercept
n = number of loads
Since graph starts from the origin (0, 0), y - intercept 'b' will be 0.
Two points lying on the line are (0, 0) and (1, 2000)
Slope of the line 'm' =
=
=2000
Therefore, equation will be,
W = 2000n
Option (C) will be the answer.
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Note necessary facts about isosceles triangle ABC:
- The median CD drawn to the base AB is also an altitude to tha base in isosceles triangle (CD⊥AB). This gives you that triangles ACD and BCD are congruent right triangles with hypotenuses AC and BC, respectively.
- The legs AB and BC of isosceles triangle ABC are congruent, AC=BC.
- Angles at the base AB are congruent, m∠A=m∠B=30°.
1. Consider right triangle ACD. The adjacent angle to the leg AD is 30°, so the hypotenuse AC is twice the opposite leg CD to the angle A.
AC=2CD.
2. Consider right triangle BCD. The adjacent angle to the leg BD is 30°, so the hypotenuse BC is twice the opposite leg CD to the angle B.
BC=2CD.
3. Find the perimeters of triangles ACD, BCD and ABC:
4. If sum of the perimeters of △ACD and △BCD is 20 cm more than the perimeter of △ABC, then
5. Since AC=BC=2CD, then the legs AC and BC of isosceles triangles have length 20 cm.
Answer: 20 cm.