We have the expression:
3x(x-12x) + 3x^2 - 2(x-2)^2
First, we will expand the power 2 bracket as follows:
3x(x-12x) + 3x^2 - 2(x^2 - 4x +4)
Then, we will get rid of the brackets as follows:
3x^2 - 36x^2 + 3x^2 - 2x^2 + 8x - 8
Now, we will gather the like terms and add them as follows:
-32 x^2 + 8x - 8
We can take the 8 as a common factor:
8 ( -4x^2 + x -1)
Let the distance of the first part of the race be x, and that of the second part, 15 - x, then
x/8 + (15 - x)/20 = 1.125
5x + 2(15 - x) = 40 x 1.125
5x + 30 - 2x = 45
3x = 45 - 30 = 15
x = 15/3 = 5
Therefore, the distance of the first part of the race is 5 miles and the time is 5/8 = 0.625 hours or 37.5 minutes
The distance of the second part of the race is 15 - 5 = 10 miles and the time is 1.125 - 0.625 = 0.5 hours or 30 minutes.
the expected value for the 3 point shot = (3 * 0.30) + (0 * 0.70) = 0.90
the expected value for the 2 point shot = (2 * 0.48) + (0 * 0.52) = 0.96
the expected value for the 2 point shot is higher than the 3 point shot so he should pass the ball
