In a certain small town there were 50 babies born in one year. Of these 50 babies, 30 were girls and 20 were boys. To investigat
e this data, a doctor ran a simulation on a computer where 50 coins were flipped 1000 times. The number of heads out of 50 flips was 30 or more 98 times. Do these results prove that girl babies are more likely than boy babies in that town?
1 answer:
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Answer:
14.86 knots.
Step-by-step explanation:
<em>Given that:</em>
The boats leave the port at noon.
Speed of boat 1 = 12 knots due east
Speed of boat 2 = 8 knots due south
At 2 pm:
Distance traveled by boat 1 = 24 units due east
Distance traveled by boat 2 = 16 units due south
Now, speed of boat 1 changes to 9 knots:
At 3 pm:
Distance traveled by boat 1 = 24 + 9= 33 units due east
Distance traveled by boat 2 = 16+8 = 24 units due south
Now, speed of boat 1 changes to 8+7 = 15 knots
At 5 pm:
Distance traveled by boat 1 = 33 + 2 9= 51 units due east
Distance traveled by boat 2 = 24 + 2 15 = 54 units due south
Now, the situation of distance traveled can be seen by the attached right angled .
O is the port and A is the location of boat 1
B is the location of boat 2.
Using pythagorean theorem:
so, the total distance between the two boats is 74.28 units.
Change in distance per hour =
Answer:
a) We need to conduct a hypothesis in order to check if the true average number of days in the past month that adults walked for the purpose of health or recreation is lower than 5.5 days (a;ternative hypothesis) , the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
b) For this case since we want to determine if the true mean is lower than an specified value is a one tailed test
c) For this case the significance level is given and we want to find the critical value, so we need to find a critical value on the normal standard distribution who accumulate 0.01 of the area on the right tail and if we use excel or a table we got:
And the rejection zone would be:
And the region is on the figure attached
Step-by-step explanation:
Part a: State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the true average number of days in the past month that adults walked for the purpose of health or recreation is lower than 5.5 days (a;ternative hypothesis) , the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
Part b
For this case since we want to determine if the true mean is lower than an specified value is a one tailed test
Part c
For this case the significance level is given and we want to find the critical value, so we need to find a critical value on the normal standard distribution who accumulate 0.01 of the area on the right tail and if we use excel or a table we got:
And the rejection zone would be:
And the region is on the figure attached
