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NARA [144]
2 years ago
12

Henry and Liani have 200 feet of wood to frame a flower bed. Henry wants the bed to be a square, while Liani wants it to be a re

ctangle with dimensions of 55 feet and 45 feet. Which statement is true regarding the areas of the two flower beds?
Mathematics
1 answer:
uranmaximum [27]2 years ago
4 0
Henrys design would result in a larger flower bed because its area would be 2500 square feet 
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Based on the graph shown to the right, whose phones cost varies directly with the amount of time spent talking?
Lena [83]

Answer:

B

Step-by-step explanation:

Given 2 quantities that vary directly, then the graph must pass through the origin.

Nikiya's graph is the only one to do this ⇒ B



8 0
2 years ago
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1. Which formula defines the sequence f(1)=2, f(2)= 6, f(3)= 10, f(4)= 14, f(5)= 18?
Natasha_Volkova [10]

Answer:

f(n) =4 + f(n-1) \\for\ n>2

Step-by-step explanation:

Given

f(1)=2\\ f(2)= 6\\ f(3)= 10\\ f(4)= 14\\ f(5)= 18

Required

Determine the formula

First, we need to solve common difference (d)

d = f(n) - f(n-1)

Take n as 2

d = f(2) - f(2-1)

d = 6 - 2

d = 4

Represent each function as a sum of the previous

f(1) = 2

f(2) = 2 + 4 = f(1) + 4

f(3) = 6 + 4 = f(2) + 4

f(4) = 10 + 4 = f(3) + 4

f(5) = 14 + 4 = f(4) + 4

Represent the function as f(n)

f(n) =f(n-1) + 4

Reorder

f(n) =4 + f(n-1) \\for\ n>2

7 0
2 years ago
5 Adoncia makes a scale drawing of the front of
Molodets [167]

Answer:

Since the length of the drawing is 200 ft. and equivalent to 13.33 in. with a scale of 15 ft to 1 in. and the length of the paper is 11 in., Adoncia's drawing will not fit on the sheet of paper

Step-by-step explanation:

The given parameters are;

The scale of the drawing is 15 ft = 1 in.

The actual dimensions of the monument;

Height = 80 ft.

Length = 200 ft.

Therefore, we have;

The required dimension of the paper height = 80/15 = 16/3 = 5.33 in.

The required dimension of the paper length = 200/15 = 40/3 = 13.33 in.

The given paper dimension by 11 in. which is of a dimension of that of a standard  letter paper size of 8.5 in. by 11 in.

Drawing length, 13.33 in. > Paper length > 11 in.

Adoncia's drawing will not fit on the sheet of paper.

4 0
2 years ago
The perimeter of a triangle is 170 ft and the sides are in the ratio of 25:14:12. Find the area of the triangle
EastWind [94]

using the ratio, the length of the sides are:

25x + 14x + 12x = 170

51x = 170

x = 170 / 51

x = 3 1/3

The lengths of the sides are: 25 * 3 1/3 = 83 1/3 feet

14 x 3 1/3 = 46 2/3 feet

12 x 3 1/3 = 40 feet

Using Heron's formula

the semi perimeter (S) = 170/2 = 85 ft.

The area of the triangle = SQRT(S*(S-83 1/3) * (S - 46 2/3) * (S-40))

= SQRT (85 * (85-83 1/3) * (85 - 46 2/3) * (85-40)

= SQRT (85 * 1 2/3 * 38 1/3 * 45)

= SQRT(244374)

= 494.34 square feet ( round answer as needed).

8 0
2 years ago
Which construction might this image result from?
Alex17521 [72]
Option (C.) is the correct answer!
Construction of the perpendicular bisector..!!!
5 0
2 years ago
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