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lesya [120]
2 years ago
7

Eddy's yard is 12 feet wide and 20 feet long. It is covered with grass.

Mathematics
1 answer:
Luba_88 [7]2 years ago
8 0

Answer:

The answer is 32

Step-by-step explanation:

12 plus 20

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A caterer makes 3 extra sandwhiches for every 20 sandwhiches a customer orders. What is the ratio of ordered sandwiches to extra
VMariaS [17]
You can solve this by making a proportion.

\frac{3}{20} =  \frac{x}{184}

you cross multiply and divide to solve this. your answer is 8.

4 0
2 years ago
Jake's morning run was a distance of 9.3 miles. He ran back and forth on one long straight street. He started at his house and r
Sergeeva-Olga [200]

Answer: the distances can be 0.65 miles (in the opposite direction to the school) or 4.65 miles (in the same direction as the school)

Step-by-step explanation:

Ok, the data that we have is:

Total distance = 9.3 mi.

The travel is:

House to school = 4 mi.

school to library = A

library to house = B

Now, we have that:

4mi + A + B = 9.3mi.

We have three possibilities:

1) The order of locations is: house, library, school

The travel from: school to library + library to house is equivalent to a travel between the school to the house = 4mi.

Then we have A + B = 4mi

4mi + A + B = 8mi ≠ 9.3mi

Then the library can not be between the house and the school.

2) The order of locations is: house, school, library.

In this case we have that the distance between the library and the house is equal to the distance between the house and the school plus the distance between the school and the library, then:

4mi + A = B.

We can replace this in our original equation:

4mi + A + B = 9.3mi

4mi  + A + (4mi + A) = 9.3mi

8mi + 2*A = 9.3mi

2*A = 9.3mi - 8mi = 1.3mi

A = 1.3mi/2 = 0.65mi

Then the distance between the house and the library is:

The 4 miles between the house and the school, plus the 0.65 miles between the school and the library:

Distance = 4mi + 0.65mi. = 4,65mi

3) The third case is when the order of the locations is:

Library, house, school.

Then the distance between the house and the library is equal to the distance between the school and the library minus the distance between the house and the school, this is:

A - 4mi = B

Now we can replace this in our distance equation:

4mi + A + B = 9.3mi

4mi + A + (A - 4mi) = 9.3 mi

2A = 9.3mi

A = 9.3mi/2 = 4.65mi

Then the distance between the house and the library is:

B = A - 4mi = 4.65mi - A = 0.65mi

Then the distance between the house and the library is 0.65 miles in this case.

7 0
2 years ago
A player hit a serve in a racket sport that was clocked at 129 mph. how much work did he have to do on the 2-oz ball to get that
djyliett [7]

Answer:

1 × 10² J

Step-by-step explanation:

Given data

  • Speed (v): 57.7 m/s

\frac{129mi}{h} .\frac{1609.34m}{1mi} .\frac{1h}{3600s} =57.7m/s

  • Mass (m): 0.06 kg

2 oz × (1 kg/35.274 oz) = 0.06 kg

The work exerted by the player is equal to the kinetic energy (K) adquired by the ball.

K = 1/2 × m × v²

K = 1/2 × 0.06 kg × (57.7 m/s)²

K = 1 × 10² J

5 0
2 years ago
An error occured while editing the question<br>Your question must be between 20 and 5000 characters
Rom4ik [11]
Well maybe you need to redo the question
8 0
2 years ago
Read 2 more answers
For quality control​ purposes, a company that manufactures sim chips for​ cell/smart phones routinely takes samples from its pro
ololo11 [35]

Answer:

There is a 22.42% probability that a sample in this size has 2 imperfections.

Step-by-step explanation:

For each chip, there are only two possible outcomes. Either they are imperfect, or they are not.

This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem

A success is a chip being imperfect. Suppose the average number of imperfections per 1000 sim chips is 3. So \pi = \frac{3}{1000} = 0.003.

What is the probability that a sample this size​ (1000 chips) has 2​ imperfections?

The sample has 1000 chips, wo n = 1000

We want P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{1000,2}.(0.003)^{2}.(0.997)^{998} = 0.2242

There is a 22.42% probability that a sample in this size has 2 imperfections.

7 0
2 years ago
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