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SIZIF [17.4K]
2 years ago
10

Tim Duncan is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one,

and he makes his free throws 72\%72%72, percent of the time.
What is the probability of Tim Duncan making all of his next 8 free throw attempts?
Mathematics
1 answer:
Leviafan [203]2 years ago
5 0

Answer:

7.2%

Step-by-step explanation:

P = (0.72)⁸

P ≈ 0.072

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Q. You are working on an air conditioning system. A roll of cylindrical copper tubing has an outside diameter of 7/8 inch and an
diamong [38]

The refrigerant can hold 1.92 ft³

Step-by-step explanation:

The formula to apply is that of volume

v=π *r²*h where v is volume, r is radius of cylindrical object and h is height   of tubing

Finding volume of using outside  diameter

v=π*7/16*7/16*12

v=49/64 *3/1 *3.14

v=7.22 ft³

Volume using inside diameter

v=π*r²*h

v=3.14*3/8*3/8*12

v=5.30 ft³

Volume the refrigerant  can hold is;

7.22-5.30 = 1.92 ft³

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Volume of a cylindrical object:brainly.com/question/2665971

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5 0
2 years ago
American households spent an average of about $52 in 2007 on Halloween merchandise such as costumes, decorations and candy. To s
Grace [21]

Answer:

The sample mean is$ 52

The claimed population mean is $58

Step-by-step explanation:

American households spent an average of about $52 in 2007 on Halloween merchandise such as costumes, decorations and candy. This tells you that the sample mean is$ 52.

1500 households were surveyed in 2008 and found an average spending of $58 0n Halloween tell us that the claim's population mean is $58

6 0
2 years ago
HELP MEEEEEEEEEE Package A contains 3 birthday cards and 2 thank-you notes and costs $9.60. Package B contains 8 birthday cards
hodyreva [135]

Answer:

Each birthday card costs $2.2 ⇒ answer c

Step-by-step explanation:

* Lets explain how to solve the problem

- Package A contains 3 birthday cards and 2 thank-you notes

- It costs $9.60

- Package B contains 8 birthday cards and 6 thank-you notes

- It costs $26.60

- x represents the cost of birthday card and y represents the cost of

 thank-you note

* Lets change these information to two equations

∵ x represents the cost of each birthday cards

∵ y represents the cost of each thank-you notes

∵ Bag A contains 3 birthday cards and 2 thank-you notes

∵ Bag A costs $9.60

∴ 3x + 2y = 9.60 ⇒ (1)

∵ Bag B contains 8 birthday cards and 6 thank-you notes

∵ Bag B costs $26.60

∴ 8x + 6y = 26.60 ⇒ (2)

* Lets solve this system of equations to find x and y

- Multiply equation (1) by -3 to eliminate y

∵ -3(3x) + -3(2y) = -3(9.60)

∴ -9x - 6y = -28.8 ⇒ (3)

- Add equations (2) and (3)

∴ -x = -2.2

- Multiply both sides by -1

∴ x = 2.2

∵ x represents the cost of each birthday cards

∴ The cost of each birthday card is $2.2

* Each birthday card costs $2.2

6 0
2 years ago
Read 2 more answers
Determine which functions have two real number zeros by calculating the discriminant, b2 – 4ac. Check all that apply. Please ans
timama [110]
<span>The discriminant of a quadratic equation is the b^2-4ac portion that the square root is taken of. If the discriminant is negative, then the function has 2 imaginary roots, if the discriminant is equal to 0, then the function has only 1 real root, and finally, if the discriminant is greater than 0, the function has 2 real roots. So let's look at the equations and see which have a positive discriminant. f(x) = x^2 + 6x + 8 6^2 - 4*1*8 36 - 32 = 4 Positive, so f(x) has 2 real roots. g(x) = x^2 + 4x + 8 4^2 - 4*1*8 16 - 32 = -16 Negative, so g(x) does not have any real roots h(x) = x^2 – 12x + 32 -12^2 - 4*1*32 144 - 128 = 16 Positive, so h(x) has 2 real roots. k(x) = x^2 + 4x – 1 4^2 - 4*1*(-1) 16 - (-4) = 20 Positive, so k(x) has 2 real roots. p(x) = 5x^2 + 5x + 4 5^2 - 4*5*4 25 - 80 = -55 Negative, so p(x) does not have any real roots t(x) = x^2 – 2x – 15 -2^2 - 4*1*(-15) 4 - (-60) = 64 Positive, so t(x) has 2 real roots.</span>
4 0
2 years ago
Read 2 more answers
Consider two unique parallel lines. what aspects of these two lines are the same? what aspects of these two lines would have to
kramer

If you have edunuity, the answer is... Two parallel lines will have the same slope. The slopes of parallel lines have to be equal. The y-intercepts of those two lines have to be different, otherwise they would be the same line. The x-intercepts of the parallel lines would also be different.

8 0
2 years ago
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