Answer:
In order for a product to be even, at least one factor must be even (so that the product is divisible by 2). The minimum number of even integers she could have chosen is 1, so the maximum number of odd integers she could have chosen is 4 :)
NB- Solution is emboldened
import java.util.Scanner;
import java.util.Random;
public class RandomGenerateNumbers {
public static void main (String [] args) {
Random randGen = new Random();
int seedVal = 0;
seedVal = 4;
randGen.setSeed(seedVal);
System.out.println(randGen.nextInt(50) + 100);
System.out.println(randGen.nextInt(50) + 100);
return;
}
}
Consider triangle XYZ with vertices at points X(1,-3), Y(3,0) and Z(-1,-1). If triangle XYZ is reflected across the line y = 1, then the rule of reflection is
(x,y)→(x,-y+2).
The image X' of point X will have coordinates according to the given rule:
X(1,-3)→X'(1, -(-3)+2)=X'(1,5).
Answer: correct choice is D.
Answer:
"76°" is the appropriate solution.
Step-by-step explanation:
Please find attachment of the diagram according to the given query.
The given values are:
In ΔDEF,
f = 610 inches
e = 590
∠E = 70°
∠F = ?
By using the law of sines, we get
⇒ 
On substituting the values, we get
⇒ 
On applying cross multiplication, we get
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
now,
⇒ 
⇒ 
Let the number of nickels found be n, the number of dimes be d and the number of quarters be q.
i) "you have twice as many quarters as dimes and 42 coins in all."
means that 2d=q, and n+d+q=42
we can reduce the number of unknowns by substituting q with 2d:
n+d+q=42
n+d+2d=42
n+3d=42
We can write all n, d and q in terms of d as follows:
there are n=42-3d nickels, d dimes and q=2d quarters.
ii) In total there are $6.60 dollars,
1 nickel = 5 cent = $0.05
1 dime = 10 cent = $0.1
1 quarter = 25 cent = $0.25
thus
(42-3d)*0.05 + d*0.1 +2d*0.25= $6.60
2.1 - 0.15d+0.1d+0.5d=6.60
2.1+0.45d=6.6
0.45d=6.6-2.1=4.5
d=4.5/0.45=10
iii)
so, there are 10 dimes, 2d=2*10=20 quarters and 42-3d=42-3*10=12 nickels.
Answer: 10 dimes, 20 quarters, 12 nickels
