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Arlecino [84]
2 years ago
6

Using the quadratic formula to solve 11x2 – 4x = 1, what are the values of x? StartFraction 2 Over 11 EndFraction plus-or-minus

StartFraction StartRoot 15 EndRoot Over 11 EndFraction StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction 2 StartRoot 15 EndRoot Over 11 EndFraction StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 7 EndRoot Over 11 EndFraction StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 7 EndRoot i Over 11 EndFraction
Mathematics
2 answers:
slamgirl [31]2 years ago
7 0

Answer:

x=\frac{2}{11}\pm\frac{\sqrt{15}} {11}

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

11x^{2} -4x=1  

equate to zero

11x^{2} -4x-1=0  

so

a=11\\b=-4\\c=-1

substitute in the formula

x=\frac{-(-4)\pm\sqrt{-4^{2}-4(11)(-1)}} {2(11)}

x=\frac{4\pm\sqrt{60}} {22}

x=\frac{4\pm2\sqrt{15}} {22}

x=\frac{2\pm\sqrt{15}} {11}

x=\frac{2}{11}\pm\frac{\sqrt{15}} {11}

therefore

StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 15 EndRoot Over 11 EndFraction

Mekhanik [1.2K]2 years ago
4 0

Answer:

a on edg

Step-by-step explanation:

took the test

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Option-1 : (-3,0)
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Answer:

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Step-by-step explanation:

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Therefore, we get

2+4+6+8+...+72+74+76+78=1560

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