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marin [14]
2 years ago
15

PLEASE HELP NEED TO PASS!!!!!!!!The graph shows the relationship between the number of ounces of cereal in a box and the price o

f the cereal. What is the correlation between the weight and price of a box of cereal? none positive negative constant
none
positive
negative
constant

Mathematics
2 answers:
Sergio039 [100]2 years ago
4 0

For this case, the first thing we must do is observe the relationship between the variables:

Independent variable: Weight of the box (ounces)

Dependent variable: Price of the box ($)

Observing the behavior between both variables, we see that there is no specific relationship between the increase or decrease in the weight of the box and the increase or decrease in the price.

Therefore, there is no correlation between the variables.

Answer:

the correlation between the weight and price of a box of cereal is:

none

slavikrds [6]2 years ago
3 0
Its the first answer "none".
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Let the distance of the first part of the race be x, and that of the second part, 15 - x, then
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Find two complex numbers that have a sum of i10 a different of -4and a product of -29​
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<h2>-2+5i and 2+5i</h2>

Step-by-step explanation:

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(a+c)+i(b+d)=10i ⇒ a+c=0,b+d=10

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a=-2,c=2,b=5,d=5

(a+ib)(c+id)=(-2+5i)(2+5i)=-4-25=-29

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"A consultant compiled the following data set that shows" the number of visits made to the National Museum of American History f
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Step-by-step explanation:

The best option is for the consultant to remove these data points because they are outliers.  Unusual data points which are located far from rest of the data points are known as outliers.

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Answer:

One can be 99% confident the true mean shell length lies within the above interval.

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We are given that Time-depth recorders were deployed on 6 of the 76 captured turtles. These 6 turtles had a mean shell length of 51.3 cm and a standard deviation of 6.6 cm.  

The pivotal quantity for a 99% confidence interval for the true mean shell length is given by;

                    P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean shell length = 51.3 cm

             s = sample standard deviation = 6.6 cm

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Now, the 99% confidence interval for \mu =  \bar X \pm t_(_\frac{\alpha}{2}_)  \times \frac{s}{\sqrt{n} }

Here, \alpha = 1% so  (\frac{\alpha}{2}) = 0.5%. So, the critical value of t at 0.5% significance level and 5 (6-1) degree of freedom is 4.032.

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The interpretation of the above result is that we are 99% confident that the true mean shell length lie within the above interval of [40.44 cm, 62.16 cm].

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3 0
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