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kari74 [83]
2 years ago
12

Carlie runs two different business. She needs to pay $100 for materials, and pay her associates $12 per hour for

Mathematics
1 answer:
Marrrta [24]2 years ago
3 0

Answer:

375+12ct_c+10lt_l

Step-by-step explanation:

Carlie is running two different business.

She needs to pay:

- For the childcare business,

100$ for the materials

12$ per hour for each associate for her childcare business, so if we call:

t_c = the number of hours worked by each associate

c = the number of associates

The total cost for the childcare business is:

C=100+12ct_c (1)

- For the lawn care business,

275$ for the materials

10$ per hour for each associate for her lawn care business, so if we call:

t_l = the number of hours worked by each associate

l = the number of associates

The total cost for the lawn care business is:

L=275+10lt_l (2)

Therefore, the total expenses from both businesses is the sum of (1) and (2):

T=C+L=100+12ct_c+275+10lt_l = 375+12ct_c+10lt_l

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During a certain week, a post office sold Rs.280 worth of 14-paisas stamps. How many of these stamps did they sell?
Novosadov [1.4K]
So basically ...

You convert the rupees in paisas. One rupee is equal to one hundred paisas, so ...

280 × 100 = 28,000

And then we divide,

28,000 ÷ 14 = 2000

The post office sold 2000 stamps!

Hope this helped! :)
6 0
2 years ago
What number is represented by 4x²+17x+2 if x=10?
Fynjy0 [20]

Answer:

at x = 10,   4x^{2}  + 17x + 2  = 572

Step-by-step explanation:

The given equation is 4x^{2}  + 17x + 2

Here, lets substitute the value of x = 10

So, the equation simplifies to ,

4 \times (10)^{2}  + 17(10) + 2

= (4 x 100)  + 170 + 2 = 400 + 170 + 2

= 572

So, at x = 10,   4x^{2}  + 17x + 2 = 572

4 0
1 year ago
John is selling his pizza for $6 per slice in an area of high demand. However, customers are not buying his pizza.
elena-14-01-66 [18.8K]
For starters lower the price
6 0
2 years ago
Read 2 more answers
The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillat
Greeley [361]

Answer:

1) L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

2) T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

3) T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

Step-by-step explanation:

Part 1

For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.

L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

Part 2

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

Part 3

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

Replacing we got:

T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

8 0
2 years ago
Two weeks ago, Alice came home from vacation and noticed that a bean plant was growing in her garden. Today, the stalk is $452$
dimulka [17.4K]
So, on day 1, the plant was say "P" cm tall.

then 2 weeks go by, or 14 days, and the plant grew to 452 cm.

\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=P(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\to 452\\
P=\textit{initial amount}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
t=\textit{elapsed time}\to &14\\
\end{cases}
\\\\\\
452=P(1+0.05)^{14}\implies \cfrac{452}{1.05^{14}}=P
7 0
2 years ago
Read 2 more answers
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