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Harrizon [31]
2 years ago
6

A game has 3 possible outcomes, with probabilities p1, p2, and p3. The amount of money that you will win or lose for each outcom

e is v1, v2, and v3, respectively. What is the expression p1v1 + p2v2 + p3v3 equal to?
Mathematics
1 answer:
Monica [59]2 years ago
8 0
We have the following given
p1 - probability for outcome 1
p2 - probability for outcome 2
p3 - probability for outcome 3
v1 - amount of money that you will win or lose for outcome 1
v2 - amount of money that you will win or lose for outcome 2
v3 - amount of money that you will win or lose for outcome 3

Therefore,
p1v1 + p2v2 + p3v3 is the average money you win or lose in playing the game.
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Orin solved an equation and justified his steps as shown in the table.
sergij07 [2.7K]

Answer:

Step-by-step explanation:

Given the equation as

\frac{3x}{5} -3=12

apply multiplication property of equality where you multiply every term by 5

\frac{3x}{5}*5 -3*5=12*5

3x-15=60------------------apply addition property of equality

3x-15+15=60+15

3x=75--------------------------appy division property of equality by dividing both sides by 3

3x/3=75/3

x=25

6 0
2 years ago
Express Rs 1.50 as a percentage of 200 cents
Juli2301 [7.4K]

1 $ = 100 cents

1.5 $ = 150 cents

1.50 $ a percentage of 200 cents = (150/200)100= 75%

3 0
2 years ago
On a coordinate plane, a triangle has points (negative 5, 1), (2, 1), (2, negative 1).
daser333 [38]

Answer:

Step-by-step explanation:

Given a triangle has points:

(-5,1),(2,1), (2,-1)

Let us label the points:

A(2,1),

B(-5,1) and  

C(2,-1)

To find:

Distance between (−5, 1) and (2, −1) i.e. BC.

Horizontal leg AB and

Vertical leg, AC.

Solution:

Please refer to the attached diagram for the labeling of the points on xy coordinate plane.

We can simply use Distance formula here, to find the distance between two coordinates.

Distance formula :

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

For BC:

x_2 = 2\\x_1 = -5\\y_2 = -1\\y_1 = 1

BC = \sqrt{(2--5)^2+(-1-1)^2} = \sqrt{63}

Horizontal leg, AC:

x_2 = -5\\x_1 = 2\\y_2 = 1\\y_1 = 1

AC = \sqrt{(2-(-5))^2+(1-1)^2} = 7

Vertical Leg,  AB:

x_2 = 2\\x_1 = 2\\y_2 = -1\\y_1 = 1

AB = \sqrt{(2-2)^2+(-1-1)^2} = 2

5 0
2 years ago
Read 2 more answers
In a group of 90 students, 65 watch rugby, 71 play a sport and 15 do neither.
Dimas [21]

Answer:

\frac{14}{75} probability of selecting a student who plays a sport but does not watch rugby out of the people who play a sport.

Step-by-step explanation:

"Find the probability that a student chosen at random from those who play a sport  does not watch rugby."

90-15= 75 students either play a sport OR watch rugby

65+71-75=

136-75=

61 people play a sport AND watches rugby

14 people play a sport and DOES NOT watch rugby

\frac{14}{75} is the probability of selecting a student who plays a sport but does not watch rugby out of the people who play a sport.

4 0
2 years ago
Consider f(x) = 1.8x – 10 and g(x) = −4. A 2 column table with 6 rows. The first column, x, has the entries, negative 4, 0, 2, 4
viktelen [127]

Answer:1.8x – 10 = –4; x = 1.8 x minus 10 equals negative 4; x equals StartFraction 10 Over 2 EndFraction.

1.8 - 10= -4 x= -10/9

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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