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KIM [24]
2 years ago
15

You want to put tape on the ground to mark the lines for a volleyball court. What is the most effi cient way to make sure that t

he opposite sides of the court are parallel? Support your answer with a diagram.
Mathematics
2 answers:
const2013 [10]2 years ago
7 0
Measure the same distance from the first line to the next at at least three points on the line to get it parallel
Nana76 [90]2 years ago
6 0
Hello <span>Dannie12 

Question: </span><span>You want to put tape on the ground to mark the lines for a volleyball court. What is the most effi cient way to make sure that the opposite sides of the court are parallel? Support your answer with a diagram.
</span><span>

Answer: Measure the same distance between every point


Hope that helps
-Chris


</span>
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You multipy 0.04 x 780
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Tran has a credit card with a spending limit of $2000 and an APR (annual percentage rate) of 12%. During the first month, Tran charged $450 and paid $150 of that in his billing cycle.

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1 year ago
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Let $f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$. Without using long division (which would be horribly nasty!), find the remainder when
valentina_108 [34]

Solution:

f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5

We have to find the remainder when f(x) is divided by x^2-1.

x²-1=0

x=\pm1

f(1)=1^{10}-8(1)^8-8(1)^3+12(1)^2-5(1)-5=1-8-8+12-5-5=1-16+12-10=13-26=-13\\\\f(-1)=(-1)^{10}-8(-1)^8-8(-1)^3+12(-1)^2-5(-1)-5=1-8+8+12+5-5=1+12=13

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1 year ago
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Biologists stocked a lake with 240 fish and estimated the carrying capacity (the maximal population for the fish of that species
LUCKY_DIMON [66]

Answer:

2.30 years

Step-by-step explanation:

The number of fish tripled in the first year, making a total of 240 * 3 = 720 fishes.

(a) The formula for logistic equation is as the following

P = P_0e^{kt}

where P0 = 240 is the number of fishes initially, we can plug in P = 720 and t = 1 to calculate the constant k

720 = 240e^{1k}

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b) Using the following formula

P = P_0e^{kt}

with P = 3000, P0 = 240, k = 1.1, we can calculate the number of years it takes to get to 3000 fishes

3000 = 240e^{1.1t}

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1.1t = ln12.5 = 2.53

t = 2.30 years

6 0
2 years ago
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