Amount of walnuts=
Amount of almonds=
Amount of pecans=
Total amount=
LCM is 4 so sum is =
=
As given, Carmela divides the mixed nuts into 3/10 kilogram bags so number of bags will be:

=
= 5
Hence, answer is 5 bags.
Answer:
−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3
Step-by-step explanation:
(p2qr+pq2r+pqr2)((−p)(q)+qr+−pr)
(p2qr)((−p)(q))+(p2qr)(qr)+(p2qr)(−pr)+(pq2r)((−p)(q))+(pq2r)(qr)+(pq2r)(−pr)+(pqr2)((−p)(q))+(pqr2)(qr)+(pqr2)(−pr)
−p3q2r+p2q2r2−p3qr2−p2q3r+pq3r2−p2q2r2−p2q2r2+pq2r3−p2qr3
−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3
Answer: The greatest number of plates Lenin can prepare = 4
and there will be 3 chickens and 4 rolls in each plate.
Step-by-step explanation:
Given: Lenin is preparing dinner plates. He has 12 pieces of chicken and 16 rolls.
To make all the plates identical without any food left over, the greatest number of plates Lenin can prepare = G.C.D.(12,16)=4
The number of pieces of chicken in each plate = 
The number of pieces of rolls in each plate = 
So, the greatest number of plates Lenin can prepare = 4
and there will be 3 chickens and 4 rolls in each plate.