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2 years ago

Which recursive formula can be used to generate the sequence below, where f(1) = 6 and n ≥ 1?

Mathematics

2 answers:

Liono4ka [1.6K]2 years ago

8 0

Answer:

optian 2

Step-by-step explanation:

Trava [24]2 years ago

4 0

f (n + 1) = f(n) – 5 is the recursive formula can be used to generate the sequence below, where f(1) = 6 and n ≥ 1

<h3>Solution:</h3>

Given that,

f(1) = 6 and n ≥ 1

Given sequence is 6, 1, -4, -9, -14

Let us first analyse the logic used in this sequence

6 - 5 = 1

1 - 5 = -4

-4 - 5 = -9

-9 - 5 = -14

Thus the next terms in sequence are obtained by subtracting 5 from previous term

Thus a recursive formula can be formed as:

f (n + 1) = f(n) – 5

Where "n" is the nth term

Let us check our recursive formula:

f(1+ 1) = f(1) - 5

f(2) = f(1) - 5

f(2) = 6 - 5 = 1

Thus we have got f(2) = 1 which is correct as per given sequence

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jake makes 9 loaves of olive bread. he uses 30 grams of olives in each loaf.he started with 1 kilogram of olives.how many grams

8090 [49]

Considering that 1 kilogram is equal to 1000 grams and he made 9 loaves of bread using 30 grams each time, that equates to 270 grams of olives. 1000 - 270 = 730. Your answer is 730 grams of olives remain. Hope this helped.

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1 year ago

What is the area of a square, in square feet, whose perimeter is 20 feet

geniusboy [140]

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=>4a = 20
=>a = 20/4
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2 years ago

Which inequality shows that Jerome wants to have read at least 85 pages by the end of Friday

Nikitich [7]

Answer:

C

Hope this helps. Have a nice day.

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1 year ago

Read 2 more answers

Dustin is standing at the edge of a vertical cliff, 40 meters high, which overlooks a clear lake. He spots a fluffy white cloud

Licemer1 [7]

Answer:

53.33 meters

Step-by-step explanation:

Let AB represents the height of the cliff,

( where, A is top and B is bottom ),

Also, C and D represents the shadow of the cloud and cloud in the sky respectively,

Suppose E is a point in the segment CD,

Such that,

AB = DE = 40 meters,

According to the question,

$m\angle CAE = 30^{\circ}$

$m\angle EAD = 60^{\circ}$

Since,

$\tan =\frac{\text{Perpendicular}}{\text{Base}}$

$\implies \tan 60^{\circ}=\frac{DE}{AE}$

$\sqrt{3}=\frac{40}{AE}$

$\implies AE = \frac{40}{\sqrt{3}}$

Now,

$\tan 30^{\circ}=\frac{CE}{AE}$

$\frac{1}{\sqrt{3}}=\frac{\sqrt{3}CE}{40}$

$\implies CE = \frac{40}{3}$

Hence,

The height of the cloud above the lake = CE + ED

$=\frac{40}{3}+40=13.33+40 = 53.33\text{ meters}$

3 0

2 years ago

What are the solutions of the compound inequality 2d + 3 ≤ –11 or 3d – 9 > 15?

pentagon [3]

Step-by-step explanation:

$2d + 3 \leqslant - 11 \\ 2d \leqslant - 11 - 3 \\ 2d \leqslant - 14 \\ \frac{2d}{2} \leqslant \frac{ - 14}{2} \\ d \leqslant - 7$

$3d - 9 > 15 \\ 3d > 15 + 9 \\ 3d > 24 \\ \frac{3d}{3} > \frac{24}{3} \\ d = 8$

Welcome

3 0

1 year ago