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2 years ago

In ΔLMN, n = 960 cm, ∠L=160° and ∠M=10°. Find the length of l, to the nearest centimeter.

Mathematics

2 answers:

Shtirlitz [24]2 years ago

4 0

Answer:

Step-by-step explanation:

Alexxandr [17]2 years ago

3 0

Answer:

1,890.8cm

Step-by-step explanation:

Sine law!! So drawing the triangle helps, We know that the angle n is 10 because 180 - 10 -160 =10. Knowing that you can now use the sine law.

x/sin160 = 960/ sin 10

x= sin 160 (5528.4)

x= 1890.8cm

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The equation y = 5.5x represents a proportional relationship. What is the constant of proportionality?

lara31 [8.8K]

Y = 5.5x
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2 years ago

Milton is floating in an inner tube in a wave pool. He is 1.5 m from the bottom of the pool when he is at the trough of a wave.

posledela

This is the concept of sinusoidal, to solve the question we proceed as follows;
Using the formula;
g(t)=offset+A*sin[(2πt)/T+Delay]
From sinusoidal theory, the time from trough to crest is normally half the period of the wave form. Such that T=2.5
The pick magnitude is given by:
Trough-Crest=
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Since the delay is at -π/2 the wave will start at the trough at [time,t=0]
substituting the above in our formula we get:
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2 years ago

What values of c and d make the equation true? RootIndex 3 StartRoot 162 x Superscript c Baseline y Superscript 5 Baseline EndRo

Reil [10]

Answer:

Step-by-step explanation:

<em>Equations </em>

We must find the values of c and d that make the below equation be true

$\sqrt[3]{162x^cy^5}=3x^2y \sqrt[3]{6y^d}$

Let's cube both sides of the equation:

$\left (\sqrt[3]{162x^cy^5}\right )^3=\left (3x^2y \sqrt[3]{6y^d}\right)^3$

The left side just simplifies the cubic root with the cube:

$162x^cy^5=\left (3x^2y \sqrt[3]{6y^d}\right)^3$

On the right side, we'll simplify the cubic root where possible and power what's outside of the root:

$162x^cy^5=3^3x^6y^3 (6y^d)$

Simplifying

$x^cy^5=x^6y^{3+d}$

Equating the powers of x and y separately we find

c=6

5=3+d

d=2

The values are

$\boxed{c=6,d=2}$

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2 years ago

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Quadrilateral ABCD is translated 7 units down and 2 units to the right.

Inessa05 [86]

It will remain the same.

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2 years ago

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Paco's cell phone carrier charges him $0.20 for each text message he sends or receives, $0.15 per minute for calls, and a $15 mo

Katarina [22]

Given:

Paco's cell phone carrier charges him $0.20 for each text message he sends or receives, $0.15 per minute for calls, and a $15 monthly service fee. Paco is trying to keep his bill for the month below $30.

To Find:

The number of texts 't' Paco can send/receive in a month.

Answer:

$0\leq t$

best describes the number of texts he can send or receive to keep his bill less than $30 in a month.

Step-by-step explanation:

Paco wants to keep is monthly bill below $30.

We see that he has to pay a foxed monthly service fee of $15. This means he is only left with a limit of $30 - $15 = $15 for his monthly calls and texts.

That is, the amount he has to pay for texting and calling has to be less than $15.

For texts, the cell phone carrier charges $0.20 for sending/receiving texts.

For calls, he is charged $0.15 per minute.

Let the number of text messages Paco can send or receive in a month be denoted by 't'.

Let the number of minutes Paco can call in a month be denoted by 'c'.

Then, the total cost of text messages he can send or receive per month would be 0.20t and the total cost of the minutes he spends on calls would be 0.15c. Together, the sum of these has to be less than $15 if his monthly bill has to be kept less than $30 (accounting for the monthly service fee).

So,

$0.20t+0.15c$

The number of texts he can send will dpend on the number of minutes he spends on his calls. For Paco to spend maximum number of texts, he has to spend 0 minutes on calls.

So, putting c = 0, the aboce equation can be written as

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$0\leq t$

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2 years ago

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