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NikAS [45]
2 years ago
14

Below is a graph of the Murphys' annual expenses. How much will the Murphys' pay in state/local taxes if their gross annual

Mathematics
2 answers:
Tcecarenko [31]2 years ago
6 0

Answer: C) 20,500.80

Step-by-step explanation:

Murrr4er [49]2 years ago
3 0

Answer:

the answer is C: 2,500.80

Step-by-step explanation:

                                                                             

You might be interested in
3 With 72 million bicycles, correct to the
Galina-37 [17]

Answer:

  181 million km

Step-by-step explanation:

"Correct to the nearest unit" means the actual value might be 1/2 unit larger (or smaller) than the reported value.

The upper bound would be the product of the maximum number of bicycles and the maximum distance each travels:

  (72.5 · 10^6 bicycles)(2.5 km/bicycle) = 181.25 · 10^6 km

__

Since the given numbers are good to 2 significant figures (or so), we might reasonably put the upper bound as 180·10^6 km.

5 0
2 years ago
Nicky writes, “If I am a bird, then I fly,” as an example of a conditional
Otrada [13]

yes   \: nicky \: is \: right
3 0
2 years ago
Read 2 more answers
Marguerite wants to rent a carpet cleaner. Company A rents a carpet cleaner for $15 per day. Company B rents a carpet cleaner fo
erma4kov [3.2K]

Answer:

see below

Step-by-step explanation:

Company A f(x) = 15(7x)

Company B g(x) = 100x + 5

If Marguerite rents for 2 weeks, it will cost her more if she rents from Company B

A = 105(2) = 210

B = 100(2) + 5 = 205   B costs less  False

f Marguerite rents for 2 weeks, it will cost her less if she rents from Company B

A = 105(2) = 210

B = 100(2) + 5 = 205   B costs less  True

If Marguerite rents for 1 week, it will cost her the same at either company

A = 105(1) = 105

B = 100(1) +5 = 105   True

If Marguerite rents for 1 week, it will cost her more if she rents from Company A  

A = 105(1) = 105

B = 100(1) +5 = 105    False

h(x) = 5x – 5  

h(x) = f(x) – g(x)

      =15(7x) - ( 100x + 5)

      = 105x - 100x -5

      = 5x-5   True

h(x) = 5x + 5  False

3 0
2 years ago
Read 2 more answers
A social scientist is interested in determining if there is a significant difference in the proportion of Republicans between tw
hodyreva [135]

Answer:

Given

p-value = 0.0156

n = 200 families

Our conclusion goes as follows:

The statistical evidence is pretty strong enough to conclude that there is a difference in the proportion of Republicans between the two areas of town because we know that small p­-value indicates significant differences, and a p­value of 0.0156 is pretty small to ascertain our conclusion.

4 0
2 years ago
Read 2 more answers
g An irate student complained that the cost of textbooks was too high. He randomly surveyed 36 other students and found that the
blagie [28]

Answer:

A 90% confidence interval of the true mean is [$119.86, $123.34].

Step-by-step explanation:

We are given that an irate student complained that the cost of textbooks was too high. He randomly surveyed 36 other students and found that the mean amount of money spent on textbooks was $121.60.

Also, the standard deviation of the population was $6.36.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                              P.Q.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean amount of money spent on textbooks = $121.60

            \sigma = population standard deviation = $6.36

            n = sample of students = 36

            \mu = population mean

<em>Here for constructing a 90% confidence interval we have used One-sample z-test statistics as we know about population standard deviation.</em>

<em />

So, 95% confidence interval for the population mean, \mu is ;

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5% level

                                                      of significance are -1.645 & 1.645}  

P(-1.645 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.645) = 0.90

P( -1.645 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

P( \bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } } ]

                                      = [ 121.60-1.645 \times {\frac{6.36}{\sqrt{36} } } , 121.60+1.645 \times {\frac{6.36}{\sqrt{36} } } ]

                                      = [$119.86, $123.34]

Therefore, a 90% confidence interval of the true mean is [$119.86, $123.34].

5 0
2 years ago
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