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kiruha [24]
2 years ago
6

Suppose that a system has 5000 grasshoppers. how many hawks would be expected?

Mathematics
1 answer:
aliina [53]2 years ago
3 0
Probably 2500 or less because they dont need that much hawks.

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If DE = 4x + 10, EF = 2x-1, and DF = 9x-15, find DF
Dmitrij [34]
Hello,
<span>We have that:
(4x+10)+(2x-1)=9x-15

</span>We solve the equation:
4x+10+2x-1=9x-15;
6x+9=9x-15;
6x-9x=-15-9;
-3x=-24;
3x=24;

<span>from which
</span>x=24:3=8

<span>Then:
DF=9x-15=(9</span>×8)-15=72-15=57

bye :-)
5 0
2 years ago
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nikki backyard is in the shape of a rectangle. the length is 27 feet. The width is one-third the length plus 4 feet. write and e
PIT_PIT [208]

Answer:

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A= 27 x (1/3 x 27 + 4)

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Step-by-step explanation:

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4 0
1 year ago
walnut grower estimates from past records that if 20 trees are planted per acre, then each tree will average 60 pounds of nuts p
laila [671]

Answer:

5 trees should be planted to maximize the yield per acre,

The maximum yield would be 1250

Step-by-step explanation:

Given,

The original number of trees per acre = 20,

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Let x be the times of increment in number of trees,

So, the new number of trees planted per acre = 20 + x

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So, the new number of pounds of nut = (60 - 2x)

Thus, the total yield per acre,

Y(x) = (20+x)(60-2x)

Differentiating with respect to t ( time ),

Y'(x) = (20+x)(-2) + 60 - 2x = -40 - 2x + 60 - 2x = 20 - 4x

Again differentiating with respect to t,

Y''(x) = -4

For maxima or minima,

Y'(x) = 0

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⇒ 20 = 4x

⇒ x = 5,

For x = 5, Y''(x) = negative,

Hence, Y(x) is maximum for x = 5,

And, maximum value of Y(x) = (20+5)(60 - 10) = 25(50) = 1250,

i.e. 5 trees should be planted to maximize the yield per acre,

and the maximum yield would be 1250 pounds

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1 year ago
A pizzeria charges $8 for a large cheese pizza, plus $2 for each topping. The total cost for a large pizza is given by the equat
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