Answer:
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Answer: On average, the weight of a pet visiting this vet on this day is about 2.4 pounds away from 12.9 pounds.
If the MAD of weights for another day was 1.5, then that day's weights would be less variable than the weights of pets seen on this day.
Step-by-step explanation:
Given: The measures in the table describe the weights of animals that visited a vet on one day, in pounds.
Mean = 12.9
Median= 12.0
Mode = 12.0
Mean Absolute Deviation = 2.4
We know that the mean absolute deviation (MAD) of a data set is the mean distance between each and every data value and the mean.It tells about the variation in a data set.
Therefore, On average, the weight of a pet visiting this vet on this day is about 2.4 pounds away from 12.9 pounds.
Also, If the MAD of weights for another day was 1.5, and since 1.5< 2.4.
Then that day's weights would be less variable than the weights of pets seen on this day.
Answer:
20 tbsp of flour OR 1.25 or 1 
cups of flour
Step-by-step explanation:
10 tbsp of flour
*2
____________
20 tbsp of flour OR 1.25 or 1 cups of flour
Answer:
Its A
Step-by-step explanation:
i just took the quiz and got it right
Answer:115 apex
Step-by-step explanation:
