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allochka39001 [22]
1 year ago
8

Trapezoid E F G H is reflected across line of reflection k to form trapezoid E prime F prime G prime H prime. Trapezoid E prime

F prime G prime H prime is shifted down to E double-prime F double-prime G double-prime H double-prime.
Which composition of transformations maps figure EFGH to figure E"F"G"H"?

a reflection across line k followed by a translation down
a translation down followed by a reflection across line k
a 180° rotation about point G followed by a translation to the right
a translation to the right followed by a 180° rotation about point G
Mathematics
2 answers:
Aleks [24]1 year ago
8 0

Answer:

Its A

Step-by-step explanation:

i just took the quiz and got it right

andrezito [222]1 year ago
3 0

Answer:

A a reflection across line k followed by a translation down

Step-by-step explanation:

EDGE 2020

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Dylan scored a total of 48 points in first 4 games of the basketball season. Which equation can be used to find g, the average n
belka [17]
G= 48/4???? that would make sense wouldn't it? because 48/4 would be the total number of points divided by the amount of games in which those points are scored. 

3 0
1 year ago
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Divide 60 kg in the ratio of 5 : 7.
CaHeK987 [17]
The ratio can be written in parts as shown below;
\frac{5}{12} : \frac{7}{12}
Then, 60 can be divided as shown below;
\frac{5}{12} *60: \frac{7}{12} *60
25kg:35kg
6 0
2 years ago
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A ball is launched into the sky at 19.6 feet per second from a 58.8 meter tall building. The equation for the ball's height. h,
Crazy boy [7]
H represents the height of the ball at a given time, symbolised as t.
Thus, we just need to find when h = 0 so that we find when it hits the ground.

0 = -4.9t² + 19.6t + 58.8
0 = 4.9t² - 19.6t - 58.8
0 = 49t² - 196t - 588
0 = t² - 4t - 12
0 = (t - 6)(t + 2)

So, t = 6 or -2, but t ≠ -2, since time cannot be negative in this instance.

Hence, at 6 seconds, the ball will strike the ground.
3 0
2 years ago
In the Fall STA 2023 Beginning of the Semester Survey, students were asked how many parties they attended every week and how man
Shtirlitz [24]

Answer:

-95.78

Step-by-step explanation:

As the researcher decided to make the number of parties attended per week the explanatory variable, this would be variable x in the regression line, and of course, the variable y would be the number of text messages sent per day.

After constructing the linear regression equation, the researcher found that an approximate value \hat y for the actual value of y could be represented by the line

\hat y=64.96+25.41x

Since this is an approximate value, it is not expected that it coincides with the actual value of y. We define then the residual for each value of x as the difference between the actual value of y and the approximation for the given x.

For the value x = 2 (the student attended 2 parties that week) the actual value of y is 20 (the student sent 20 text messages per day that week).

The approximate value of y would be according to the regression line

\hat y(2)=64.96+25.41(2)=64.96+50.82=115.78

Hence, the residual value for x=2 would be

y_{real}-\hat y=20-115.78=-95.78

5 0
2 years ago
A length is measured as 21cm correct to 2 significant figures. what is the upper bound for the length?​
Leno4ka [110]

the upper bound for the length is  21.5  cm .

<u>Step-by-step explanation:</u>

Lower and Upper Bounds

  • The lower bound is the smallest value that will round up to the approximate value.
  • The upper bound is the smallest value that will round up to the next approximate value.

Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.

Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:

As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :

⇒ 21.5  cm

21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is  21.5  cm .

7 0
2 years ago
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