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1 year ago

6

3) You find a jar of quarters on the sidewalk and decide to start collecting them to cash in at the end of the school year.

1 answer:

soldier1979 [14.2K]1 year ago

5 0

Answer:

I dont rally know

Step-by-step explanation:

try it yourself

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The product of three integers is −5. Determine all of the possible values for the three factors.

tensa zangetsu [6.8K]

-1,1,5
-1,-1,-5
1,1,-5

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2 years ago

A company makes a product and has no way to determine which ones are faulty until an unhappy customer returns it. Three percent

Vitek1552 [10]

<span>(x) - (0.03)(200) = 2.00
Let x be the </span><span>company charge to make the profit

solving for x gives 8$</span>

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2 years ago

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Identify whether the series summation of 12 open parentheses 3 over 5 close parentheses to the I minus 1 power from 1 to infinit

Finger [1]

∑ from 1 to infinity of 12(3/5)^(i - 1)
Since the common ratio is less than 1, the series is convegent. [i.e. 3/5 < 1]

Sum to infinity of a geometric series is given by a/(1 - r); where a is the first term, and r is the common ratio.

Sum = 12/(1 - 3/5) = 12/(2/5) = 30.

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2 years ago

7 divided by 423 full answer

anygoal [31]

The answer is 0.01654846336

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2 years ago

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Using the quadratic formula to solve 11x2 – 4x = 1, what are the values of x? StartFraction 2 Over 11 EndFraction plus-or-minus

slamgirl [31]

Answer:

$x=\frac{2}{11}\pm\frac{\sqrt{15}} {11}$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$11x^{2} -4x=1$

equate to zero

$11x^{2} -4x-1=0$

so

$a=11\\b=-4\\c=-1$

substitute in the formula

$x=\frac{-(-4)\pm\sqrt{-4^{2}-4(11)(-1)}} {2(11)}$

$x=\frac{4\pm\sqrt{60}} {22}$

$x=\frac{4\pm2\sqrt{15}} {22}$

$x=\frac{2\pm\sqrt{15}} {11}$

$x=\frac{2}{11}\pm\frac{\sqrt{15}} {11}$

therefore

StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 15 EndRoot Over 11 EndFraction

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2 years ago

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