On a coordinate plane, a curved line with a maximum value of (negative 1, 4) and minimum values of (negative 1.25, negative 16)
2 answers:
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Answer:
a. P(X ≤ 5) = 0.999
b. P(X > λ+λ) = P(X > 2) = 0.080
Step-by-step explanation:
We model this randome variable with a Poisson distribution, with parameter λ=1.
We have to calculate, using this distribution, P(X ≤ 5).
The probability of k pipeline failures can be calculated with the following equation:
Then, we can calculate P(X ≤ 5) as:
The standard deviation of the Poisson deistribution is equal to its parameter λ=1, so the probability that X exceeds its mean value by more than one standard deviation (X>1+1=2) can be calculated as:
Answer:
His 95% confidence interval is (0.065, 0.155).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
95% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
His 95% confidence interval is (0.065, 0.155).
Answer:
The answer is 23 years.
Step-by-step explanation:
We will use the formula :
Here P = 220
r = 3%
A = 400
Putting these values in the formula we get,
Taking log on both sides,
ln(1.03)t=ln 2
t=23.44 or rounding to nearest, t=23 years
The graph of the function can be shown as below.
