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Dvinal [7]
2 years ago
15

On a coordinate plane, a curved line with a maximum value of (negative 1, 4) and minimum values of (negative 1.25, negative 16)

and (2.5, negative 3), crosses the x-axis at (negative 2.1, 0), (0.25, 0), (1.75, 0), and (3, 0), and crosses the y-axis at (0, negative 3).
Which intervals show f(x) decreasing? Check all that apply.

[–2.5, –2]
[–2, –1.5]
[–1, 1)
[1.5, 2]
[2, 2.5)
(2.5, 3]
Mathematics
2 answers:
In-s [12.5K]2 years ago
3 0

Answer:

1+1=2

Step-by-step explanation:

Guest
1 year ago
play too much
Guest1 year ago
1 0

A,B,D,E is the answer

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A salesman used three types of order forms: A, B, C. He used 40 of Form A. Of Form B he used four times as many as Form A plus 1
aivan3 [116]

Answer:

a. 440

Step-by-step explanation:

The information provided allows us to set up the following system of linear equations:

A = 40\\B=4A+0.5C\\C=A+0.5B

We already have the value for A, solving the system gives us the values for B and C:

A = 40\\B=(4*40)+0.5C\\C=40+0.5B\\\\B -B-80 = (4*40)+0.5C-2C\\C=\frac{160+80}{1.5}\\C=160\\B= (4*40) +(0.5*160)\\B=240

The total number of forms used is:

A+B+C = 40+240+160 = 440

He used 440 forms.

4 0
2 years ago
Read 2 more answers
Traffic speed: The mean speed for a sample of cars at a certain intersection was kilometers per hour with a standard deviation o
aliina [53]

Answer:

Step-by-step explanation:

Hello!

X₁: speed of a motorcycle at a certain intersection.

n₁= 135

X[bar]₁= 33.99 km/h

S₁= 4.02 km/h

X₂: speed of a car at a certain intersection.

n₂= 42 cars

X[bar]₂= 26.56 km/h

S₂= 2.45 km/h

Assuming

X₁~N(μ₁; σ₁²)

X₂~N(μ₂; σ₂²)

and σ₁² = σ₂²

<em>A 90% confidence interval for the difference between the mean speeds, in kilometers per hour, of motorcycles and cars at this intersection is ________.</em>

The parameter of interest is μ₁-μ₂

(X[bar]₁-X[bar]₂)±t_{n_1+n_2-2} * Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }

t_{n_1+n_2-2;1-\alpha /2}= t_{175; 0.95}= 1.654

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{134*16.1604+41*6.0025}{135+42-2} } = 3.71

[(33.99-26.56) ± 1.654 *(3.71*\sqrt{\frac{1}{135} +\frac{1}{42} })]

[6.345; 8.514]= [6.35; 8.51]km/h

<em>Construct the 98% confidence interval for the difference μ₁-μ₂ when X[bar]₁= 475.12, S₁= 43.48, X[bar]₂= 321.34, S₂= 21.60, n₁= 12, n₂= 15</em>

t_{n_1+n_2-2;1-\alpha /2}= t_{25; 0.99}= 2.485

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{11*(43.48)^2+14*(21.60)^2}{12+15-2} } = 33.06

[(475.12-321.34) ± 2.485 *(33.06*\sqrt{\frac{1}{12} +\frac{1}{15} })]

[121.96; 185.60]

I hope this helps!

3 0
2 years ago
Prajna is listing squares of two-digit numbers in such a way that the digit in their units place is 6.
dem82 [27]

Answer:

2 (option B)

Question:

Prajna is listing squares of two-digit numbers in such a way that the digit in their units place is 6.

How many numbers should he have listed?

a) 9 b) 2 c)18 d) 20

Step-by-step explanation:

We would find the perfect squares that are two digit numbers

For two digit perfect squares:

Largest two digit number= 81 = 9²

Smallest two digit number= 16 = 4²

Total Two digit number perfect squares = Highest number - lowest number + 1

= 9-4+1 = 6

There are 6 two digit perfect squares

Next, we have to find how many of them have 6 in their units place.

The rule to be applied: If a number has 4 or 6 in the unit place, then its square has 6 in the units place.

Following this, the possibilities are 4², 6².

We have two of such numbers.

Therefore, he would have listed 2 numbers.

6 0
2 years ago
True or false: the regression sum of squares (ssr) can never be greater than the total sum of squares (sst).
Valentin [98]
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8 0
2 years ago
Draw a double number line to show that 6 out of 25 M&amp;Ms are green then use it to find what percent are green
Talja [164]

Answer:

Egg

Step-by-step explanation:

eggeggeggeggeggeggeggeggeggeggeggeggeggeggeggeggeggeggeggegg

4 0
2 years ago
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