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Alexeev081 [22]
2 years ago
14

Mr. Louis is taking a bus tour. The cost of the bus tour includes: $25.75 for the bus ride $9.25 for lunch admission to two muse

ums, admission cost is the same to each museum The cost of the bus ride and lunch is 58 the total cost of the bus tour. What is the cost, in dollars, of the tour? What is the admission cost, in dollars, to each museum? Enter your answers in the boxes. The cost, in dollars, of the tour is . The admission cost, in dollars, to each museum is .
Mathematics
1 answer:
Brums [2.3K]2 years ago
4 0

Answer: admission cost is 21 dollars

Step-by-step explanation:

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You just discovered that you have 100 feet of fencing and you have decided to make a rectangular garden. Assume the lengths of t
Tju [1.3M]

Answer:

10*10=100

50*2=100

5*20-100

Step-by-step explanation:


3 0
2 years ago
An engineering school reports that 53% of its students were male (M), 35% of its students were between the ages of 18 and 20 (A)
erik [133]

Answer: Our required probability is 0.65.

Step-by-step explanation:

Since we have given that

                      18-20                  Not 18-20           Total

Male                0.23                    0.35                 0.58

Female            0.16                     0.26                0.42

Total                0.39                    0.61                   1

P(female or between 18-20) = P(female) + P(18-20) - P(Female and 18-20)

P(female or between 18-20) =  0.42+0.39-0.16

P(female or between 18-20) = 0.65

Hence, our required probability is 0.65.

3 0
1 year ago
Which equation can be solved to find one of the missing side lengths in the triangle?
IrinaK [193]

Answer:

it should be D....due to the fact that opposite over adjacent for the missing length



8 0
1 year ago
In an analysis of healthcare data, ages have been rounded to the nearest multiple of 5 years. The difference between the true ag
Mars2501 [29]

Answer:

The approximate probability that the mean of the rounded ages within 0.25 years of the mean of the true ages is P=0.766.

Step-by-step explanation:

We have a uniform distribution from which we are taking a sample of size n=48. We have to determine the sampling distribution and calculate the probability of getting a sample within 0.25 years of the mean of the true ages.

The mean of the uniform distribution is:

\mu=\dfrac{Max+Min}{2}=\dfrac{2.5+(-2.5)}{2}=0

The standard deviation of the uniform distribution is:

\sigma=\dfrac{Max-Min}{\sqrt{12}}=\dfrac{2.5-(-2.5)}{\sqrt{12}}=\dfrac{5}{3.46}=1.44

The sampling distribution can be approximated as a normal distribution with the following parameters:

\mu_s=\mu=0\\\\\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.44}{\sqrt{48}}=\dfrac{1.44}{6.93}=0.21

We can now calculate the probability that the sample mean falls within 0.25 from the mean of the true ages using the z-score:

z=\dfrac{X-\mu}{\sigma}=\dfrac{0.25-0}{0.21}=\dfrac{0.25}{0.21}=1.19\\\\\\P(|X_s-\mu|

7 0
1 year ago
An in-ground pond has the shape of a rectangular prism. The pond has a depth of 24 inches and a volume of 72,000 cubic inches. T
Ksenya-84 [330]
Let
x-------> <span>the length of the pond
</span>y-------> the  width of the pond

we know that
[volume of the pond]=area of the base*deep
area of the base=volume/deep
volume=72000 in³
deep=24 in
area of the base=72000/24------> 3000 in²

area of the base=x*y
3000=x*y-------> equation 1
x=2y-----> equation 2

substitute equation 2 in equation 1
3000=[2y]*y------> 2y²=3000-----> y²=1500------> y=38.7 in
x=2y----> x=2*38.7----> x=77.4 in

the answer is
the length of the pond is 77.4 in
the  width of the pond is 38.7 in

5 0
1 year ago
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