Answer:
10*10=100
50*2=100
5*20-100
Step-by-step explanation:
Answer: Our required probability is 0.65.
Step-by-step explanation:
Since we have given that
18-20 Not 18-20 Total
Male 0.23 0.35 0.58
Female 0.16 0.26 0.42
Total 0.39 0.61 1
P(female or between 18-20) = P(female) + P(18-20) - P(Female and 18-20)
P(female or between 18-20) = 0.42+0.39-0.16
P(female or between 18-20) = 0.65
Hence, our required probability is 0.65.
Answer:
it should be D....due to the fact that opposite over adjacent for the missing length
Answer:
The approximate probability that the mean of the rounded ages within 0.25 years of the mean of the true ages is P=0.766.
Step-by-step explanation:
We have a uniform distribution from which we are taking a sample of size n=48. We have to determine the sampling distribution and calculate the probability of getting a sample within 0.25 years of the mean of the true ages.
The mean of the uniform distribution is:

The standard deviation of the uniform distribution is:

The sampling distribution can be approximated as a normal distribution with the following parameters:

We can now calculate the probability that the sample mean falls within 0.25 from the mean of the true ages using the z-score:

Let
x-------> <span>the length of the pond
</span>y-------> the width of the pond
we know that
[volume of the pond]=area of the base*deep
area of the base=volume/deep
volume=72000 in³
deep=24 in
area of the base=72000/24------> 3000 in²
area of the base=x*y
3000=x*y-------> equation 1
x=2y-----> equation 2
substitute equation 2 in equation 1
3000=[2y]*y------> 2y²=3000-----> y²=1500------> y=38.7 in
x=2y----> x=2*38.7----> x=77.4 in
the answer is
the length of the pond is 77.4 in
the width of the pond is 38.7 in