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Kobotan [32]
2 years ago
9

The 30 members of a choir are trying to raise at least $1,500 to cover travel costs to a singing camp. They already have $600. W

hich inequality could you solve to find the average amounts each member can raise in order to meet the goal?
Mathematics
1 answer:
ryzh [129]2 years ago
8 0
The choir members need $1500, but they have $600.  Therefore, they need $1500-$600=$900 more.

Call a the average amount raised by a member.  We see that 30a >= $900.  Dividing by 30, we find that a >= $30, so the average member must raise at least $30.
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ivanzaharov [21]
Anita can clean 1/8 portion of the pool in 1 hour

Chao can clean 1/6 portion of the pool in 1 hour

Both of them working together can clean 1/8 + 1/6 = 7/24 portion of the pool in 1 hour

Therefore, it will take both of the working together 1/(7/24) = 24/7 or 3 3/7 hours to clean a typical pool.
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Which measurement is the best estimate for the capacity of a bottle of nail polish?
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The best estimate for the capacity of a bottle of nail polish is A: 10 mL
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17. It takes one minute to fill (3/7) th of a vessel. What is the time taken in
Vinil7 [7]

Answer:

Given that 1minute =3/7of the vessel

let the time taken in minutes to fill the whole of the vessel be' x' minute.

1min =3/7

xmin =whole vessel =1=7/7

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8 0
2 years ago
A study was conducted to determine if there was a difference in the driving ability of students from West University and East Un
Sholpan [36]

Answer:

There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, <em>assuming a significance level 0.1</em>

Step-by-step explanation:

Let p1 be the proportion of West University students who involved in a car accident within the past year

Let p2 be the proportion of East University students who involved in a car accident within the past year

Then

H_{0}:p1=p2

H_{a}:p1≠p2

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{\frac{p*(1-p)*(n1+n2)}{n1*n2} } }  where

  • p1 is the <em>sample</em> proportion of West University students who involved in a car accident within the past year (0.15)
  • p2 is the <em>sample</em> proportion of East University students who involved in a car accident within the past year (0.12)
  • p is the pool proportion of p1 and p2 (\frac{15+12}{100+100}=0.135)
  • n1 is the sample size of the students from West University (100)
  • n2 is the sample size ofthe students from East University (100)

Then we have z=\frac{0.03}{\sqrt{\frac{0.135*0.865*(100+100)}{100*100} } } ≈ 0.6208

Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.

<em>Assuming significance level 0.1</em>, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance

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The answer is xy(27x-43y) have a great day :)
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2 years ago
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