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Sonbull [250]
1 year ago
6

Dylan has two cubes of iron. The larger cube has twice the mass of the smaller cube. He measures the smaller cube. It's mass is

20 grams, and its density is 7.87 g/cm3. What's the larger cube's volume?
Mathematics
1 answer:
Lelu [443]1 year ago
6 0
Density \rho
is given by \rho = frac{m}{V}
where m is the mass of the object
V is the Volume of the object

let m1 be the mass of the smaller cube
let m2 be the mass of the larger cube

you know that the larger cube has twice the mass of the smaller cube
or m2=2*m1

so apply this information into the density equation and you can determine the volume of the larger cube
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Efectuati impartirea 12xy:3x
adelina 88 [10]

In this question , we have to simplify the given ratio, which is

12xy:3x

First we have to see which factor is common in numerator and denominator,

We can write 12 as 3 times 4, that is

3*4x*y :3x

So the common factor is 3x.

In the next step, we cancel out 3x

4y:1

And that's the required simplified form .

7 0
2 years ago
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A sociologist wishes to see if it is true that for a certain group of professional women, the average age at which they have the
Vadim26 [7]

Answer:

Z = 2.1\ is\ higher\ than\ 1.96, we\ reject\ H_o

Step-by-step explanation:

The explanation of given question is described below:

Here, the test of hypothesis states that

H_o : Mean = 28.6

H_a : Mean\ which\ is\ not\ equals\ 28.6

The test statistic is

Z = \frac{(\bar X - Mean)}{\frac{Population\ standard\ deviation}{vn} }

Z = \frac{(30.06 - 28.6)}{\frac{4.18}{6} }

= 2.1

According to the given data α = 0.05,

So, the major value is

IZ(0.025)I = 1.96

(refer to the standard normal table) .

Finally

Z = 2.1\ is\ higher\ than\ 1.96, we\ reject\ H_o

3 0
2 years ago
Find the value of cosAcos2Acos3A...........cos998Acos999A where A=2π/1999
Lady bird [3.3K]
Hello,

Here is the demonstration in the book Person Guide to Mathematic by Khattar Dinesh.

Let's assume
P=cos(a)*cos(2a)*cos(3a)*....*cos(998a)*cos(999a)
Q=sin(a)*sin(2a)*sin(3a)*....*sin(998a)*sin(999a)

As sin x *cos x=sin (2x) /2

P*Q=1/2*sin(2a)*1/2sin(4a)*1/2*sin(6a)*....
         *1/2* sin(2*998a)*1/2*sin(2*999a) (there are 999 factors)
= 1/(2^999) * sin(2a)*sin(4a)*...
     *sin(998a)*sin(1000a)*sin(1002a)*....*sin(1996a)*sin(1998a)
 as sin(x)=-sin(2pi-x) and 2pi=1999a

sin(1000a)=-sin(2pi-1000a)=-sin(1999a-1000a)=-sin(999a)
sin(1002a)=-sin(2pi-1002a)=-sin(1999a-1002a)=-sin(997a)
...
sin(1996a)=-sin(2pi-1996a)=-sin(1999a-1996a)=-sin(3a)
sin(1998a)=-sin(2pi-1998a)=-sin(1999a-1998a)=-sin(a)

So  sin(2a)*sin(4a)*...
     *sin(998a)*sin(1000a)*sin(1002a)*....*sin(1996a)*sin(1998a)
= sin(a)*sin(2a)*sin(3a)*....*sin(998)*sin(999) since there are 500 sign "-".

Thus
P*Q=1/2^999*Q or Q!=0 then
P=1/(2^999)

       








7 0
1 year ago
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What are the vertical asymptotes of the function f(x) = the quantity of 4x plus 8, all over x squared plus 3x minus 4? plz answe
kolezko [41]

Answer:

x=1 and x=-4

Step-by-step explanation:

Put it into your calculator, go to graph and look at which points it says ERROR.

4 0
2 years ago
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Determine if this conjecture is true. If not, give a counterexample. The difference of two negative numbers is a negative number
Orlov [11]

That would be a false statement

6 0
1 year ago
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