Answer:
- Time = approximately mid 2012
- Oil import rate = 3600 barrels
Step-by-step explanation:
<h3><em>Unclear part of the question</em></h3>
- I(t) = −35t² + 800t − 1,000 thousand barrels per day (9 ≤ t ≤ 13)
- According to the model, approximately when were oil imports to the country greatest? t = ?
<h3>Solution</h3>
Given the quadratic function
- <em>The vertex of a quadratic function is found by a formula: x = -b/2a</em>
<u>As per given function:</u>
<u>Then</u>
- t = - 800/2*(-35) = 11.43 which is within given range of 9 ≤ t ≤ 13
This time is approximately mid 2012.
<u>Considering this in the function, to get oil import rate for the same time:</u>
- l(11.43) = -35*(11.43)² + 800*11.43 - 1000 = 3571.4285
<u>Rounded to two significant figures, the greatest oil import rate was</u>:
This can be solved using the formula for t test which is = x - mu over standard deviation divided by the square root of the number of samples. In this case, it is 1185 - 1200 over 70 divided by square root of 100 which give us a value of 2.14 which is equal to .9839 in area. Only rarely, just over one time in a hundred tries of 100 light bulbs, would the average life exceed 1200 hours.
57 is the answer cuz im good at math math is my thang
Step 1
<u>Find the measure of angle x</u>
we know that
If ray NP bisects <MNQ
then
m<MNQ=m<PNM+m<PNQ ------> equation A
and
m<PNM=m<PNQ -------> equation B
we have that
m<MNQ=(8x+12)°
m<PNQ=78°
so
substitute in equation A
(8x+12)=78+78-------> 8x+12=156------> 8x=156-12
8x=144------> x=18°
Step 2
<u>Find the measure of angle y</u>
we have
m<PNM=(3y-9)°
m<PNM=78°
so
3y-9=78------> 3y=87------> y=29°
therefore
<u>the answer is</u>
the measure of x is 18° and the measure of y is 29°
