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Komok [63]
2 years ago
10

Yoku is putting on sunscreen. He uses 2\text{ ml}2 ml2, start text, space, m, l, end text to cover 50\text{ cm}^250 cm 2 50, sta

rt text, space, c, m, end text, squared of his skin. He wants to know how many milliliters of sunscreen (c)(c)left parenthesis, c, right parenthesis he needs to cover 325\text{ cm}^2325 cm 2 325, start text, space, c, m, end text, squared of his skin. How many milliliters of sunscreen does Yoku need to cover 325 \text{ cm}^2325 cm 2 325, start text, space, c, m, end text, squared of his skin?
Mathematics
2 answers:
gregori [183]2 years ago
8 0

Answer:

13 is the answer!!!

Step-by-step explanation:

Kaylis [27]2 years ago
7 0

Answer:

13 Millilitres.

Step-by-step explanation:

Yoku uses 2ml to cover 50cm^2 of his skin.

He wants to know how many millilitres of sunscreen he will need to cover 325cm^2 of his body.

If Yoku covers 50cm^2 of his skin will 2ml

He will cover 1cm^2 of his skin with \frac{2}{50}ml of sunscreen.

Therefore:

To cover 325cm^2 of his body, he will use:

\frac{2}{50} X 325 ml\\=13ml

he would require 13 Millilitres.

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Miguel is a golfer, and he plays on the same course each week. The following table shows the probability distribution for his sc
stira [4]

Answer:

a. p(x<= 5) = .15 + .4 + .25 = .8

C. .4(4.2) = 1.68

5.4(1-.4) = 3.24

3.24 + 1.68 = 4.92 ,, 4.92 > 4.55 so short is better

Step-by-step explanation:

8 0
2 years ago
Which transformation maps hexagon 1 into 3?
umka2103 [35]
Let's look at the possibilities:

1. Reflection along the y-axis and rotation of 180 degrees by the origin 0. (Gives us 4 and then 2 in the end)

2. Reflection along the y-axis and reflection along the x-axis. (Gives us 4 and then 3 in the end)

3. Reflection along the x-axis and rotation 90 degrees by the origin 0. (Gives us 4 and then 1 in the end)

4. Rotation of 270 degrees by the origin 0. (Gives us 2 in the end)

Option 2 is the answer.

Best of luck!
5 0
2 years ago
Find the volume of a pyramid with a square base, where the perimeter of the base is 5.1 in 5.1 in and the height of the pyramid
lana66690 [7]

Step-by-step explanation:

PARA ENCONTRAR CUÁNTO MIDE CAD LADO SE DIVIDE EL PERÍMETRO

ENTRE 4 LADOS

l = 1.28 in

LOEGO ENCUENTRAS EL RADIO DE LA PIRÁMIDE

<em>r</em> = 2.55 in

USANDO LA FÓRMULA

V = 4(1.28 in)(2.55 in)(2.7 in)/6 = 5.9 in^{3}

6 0
2 years ago
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 nigh
lorasvet [3.4K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean GPA of night students and μ2 be the mean GPA of day students.

The random variable is μ1 - μ2 = difference in the mean GPA of night students and the mean GPA of day students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 2.35

x2 = 2.58

s1 = 0.46

s2 = 0.47

n1 = 30

n2 = 25

t = (2.35 - 2.58)/√(0.46²/30 + 0.47²/25)

t = - 1.82

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.46²/30 + 0.47²/25]²/[(1/30 - 1)(0.46²/30)² + (1/25 - 1)(0.47²/25)²] = 0.00025247091/0.00000496862

df = 51

We would determine the probability value from the t test calculator. It becomes

p value = 0.075

Alpha = 5% = 0.05

Since alpha, 0.05 < than the p value, 0.075, then we would fail to reject the null hypothesis.

4 0
2 years ago
Problem 5 (4+4+4=12) We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. 1) Fin
tekilochka [14]

Answer:

1

p(b) =  \frac{1}{6}

2

p(k) =  \frac{1}{3}

3

P(a) =  \frac{1}{3}

Step-by-step explanation:

Generally when two fair 6-sided dice is rolled the doubles are

(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)

The total outcome of doubles is N = 6

The total outcome of the rolling the two fair 6-sided dice is

n = 36

Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as

p(b) =  \frac{N}{n}

p(b) =  \frac{6}{36}

p(b) =  \frac{1}{6}

Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is

(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)

Looking at this outcome we see that there are two doubles present

So

The conditional probability that doubles were rolled is mathematically represented as

p(k) =  \frac{2}{6}

p(k) =  \frac{1}{3}

Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30

And the number of outcomes that at least one die is a 1 is W = 10

So

The conditional probability that at least one die is a 1 is mathematically represented as

P(a) =  \frac{W}{L}

=> P(a) =  \frac{10}{30}

=> P(a) =  \frac{1}{3}

3 0
1 year ago
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