11/12 of a gallon, you have to find the common denominator.
<span>1)Given: AB = 4 AD = 6
What is the name of the radius of the larger circle?
the answer part 1) is
the radius </span>of the larger circle is AD
<span>2)Given: AB = 4 AD = 6
What point is in the interior of both circles?
the answer Part 2) is
The point A (the center of the circles)
</span><span>3) Given: AB = 4 AD = 6
Which points are in the exterior of both circles?</span><span>
the answer Part 3) is
</span><span>E and G
</span><span>4)The circles are _____.
</span><span>the answer Part 4) is
</span><span>concentric
</span>
<span>5)If AC = 20 and BD = 8, what is the radius of the smaller circle?
</span>we know that
radius smaller circle=AB
and
AB=AC-BD--------> AC=20-12-------> AC=8 units
the answer part 5) is
the radius of the smaller circle is 12 units
<span>6)Given: AB = 4 AD= 6
What is the length of BD?</span>
we know that
AD=AB+BD
solve for BD
BD=AD-AB--------> BD=6-4-----> BD=2 units
the answer Part 6) is
the length of BD is 2
<span>7)Given: AB = 4 AD = 6
What is the name of the radius of the smaller circle?</span>
the answer Part 7) is
the name of the radius of the smaller circle is AB
Answer:
12a^9b^7
Step-by-step explanation:
Multiplying variables of the same base, will require you to add the exponents.
4a^3b^2 * 3a^6b^5
4*3 = 12
a^3 * a^6 = a^9
b^2 * b^5 = b^7
12a^9b^7
Isolating 2abCos(c) on one side of the equation and using the given values of a, b and c we can find the answer to this question as shown below:
