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ArbitrLikvidat [17]
2 years ago
12

Dylan can paint a wall in 4 hours, while Brett can paint the same wall in 3 hours. If Dylan paints the wall for 2 hours, how muc

h time will it take for Brett to finish painting the wall
Mathematics
1 answer:
Oksanka [162]2 years ago
8 0

Answer:

n 1 hour Dylan can paint 1/4 of the wall, and Brett can paint 1/3 of the wall.

Therefore together they can paint 1/4+1/3 = 7/12 of wall

Therefore they can paint entire wall in 12/7 hours

Step-by-step explanation:

you ' re welcome grandma loves youu ! < 33 ; )

mark meee branliest pleaseeee ; )

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A video game requires at least 4 points to advance. Each solved puzzle is worth two points. Each solved riddle is worth 1 point.
Gwar [14]

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

x -----> the number of solved puzzles

y -----> the number of solved riddles

we know that

2x+y \geq 4

The solution of the inequality is the shaded area above the solid line 2x+y=4

The slope of the solid line is negative m=-2

The y-intercept of the solid line is the point (0,4)

The x-intercept of the solid line is the point (2,0)

therefore

The graph in the attached figure

3 0
2 years ago
Read 2 more answers
You place a cup of 200 degrees F coffee on a table in a room that is 67 degrees F, and 10 minutes later, it is 195 degrees F. Ap
Marat540 [252]
195=67+(200-67)e^(-10k)

195=67+133e^(-10k)

128=133e^(-10k)

128/133=e^(-10k)

ln(128/133)=-10k

k=-ln(128/133)/10

T(t)=67+133e^(tln(128/133)/10), if T(t)=180

180=67+133e^(tln(128/133)/10)

113=133e^(tln(128/133)/10)

113/133=e^(tln(128/133)/10)

ln(113/133)=tln(128/133)/10

10ln(113/133)=tln(128/133)

t=10ln(113/133)/ln(128/133)

t≈42.5 minutes...

t≈40 minutes (to nearest 5 minutes? :P)


4 0
2 years ago
Read 2 more answers
3 freshmen and 2 sophomores from a sorority will attend a conference. If the sorority has 12 freshmen and 9 sophomores, in how m
padilas [110]

Answer:

7920

Step-by-step explanation:

12C3 × 9C2

= 220×36

= 7920

3 0
2 years ago
Read 2 more answers
Jeanne babysits for $6 per hour. She also works as a reading tutor for $10 per hour. She is only allowed to work 20 hours per we
Maru [420]
A) System of inequalities

Income from babysitting: 6x
Income from tutoring: 10y

Goal for this week: at least $ 75 => 6x + 10y ≥ 75
Number of hours: maximum $20 => x + y ≤ 20

x and y have to be zero or positvie => x≥0 and y ≥ 0

Answer of part A.

6x + 10y ≥ 75
x+y ≤ 20
x ≥ 0
y ≥ 0

Part B. Graph

The solution is a region closed by 4 lines and you can find it in the file attached.

In that graph:

1) the line x + y = 20 is the upper limit
2) the line 6x + 10 y = 75 is the lower incclined line
3) y = 0 is the botton horizontal line it is the x-axis
4) x = 0 is the left vertical line, in is the y-axis

Part C.

Use, for example the point (7,10).

It is in the region of the graph limited by the above equations.

It implies:

Number of hours worked = 7 + 10 = 17 which is less than 20.

Income: 6(7) + 10(10) = 42 + 100 = 142, which is greater than 75

Of course, both are greater than 0.

In this way we proved that the point (7,10) is a true solution for the model.






Download pdf
8 0
2 years ago
Find the 6th term of the arithmetic sequence -4, 0, 4, 8,
bezimeni [28]

Answer:

a

Step-by-step explanation:

-4,0,4,8,12,16

4 0
2 years ago
Read 2 more answers
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