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1 year ago

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A man walks 10 miles in x hours. How far does he walk in one hour? Which expression represents this? 10 + x miles 10x miles 10/x

miles

2 answers:

Oksi-84 [34.3K]1 year ago

7 0

Answer:

the answer is the third one or 10/x miles

dont forget to rate and thank :)

scoundrel [369]1 year ago

4 0

Set up a proportion:
10 miles - x hours
m miles - 1 hour

$\frac{10}{x}=\frac{m}{1} \\ \\
m=\frac{10}{x}$

The man walks 10/x miles in one hour.

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A bus traveling from Philadelphia to Boston travels at an average speed of 55 miles per hour. The bus stops for 1 hour halfway b

igor_vitrenko [27]

55t+1=310
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7 0

2 years ago

bookstore ordered 1,528 packs of pens and 1,823 packs of pencils at the prices shown. how much did the bookstore spend on pens?

IgorC [24]

I found that the given prices are $ 4 per pack of pens and $ 3 per pack of penciles.

The question is how much the bookstore spent on pens.

Then you have to multiply the number packs of pens, which is 1,528, times the price per pack pens which is $ 4.

So, the answer is: 1528 packs of pens * $ 4 / pack of pens = $6112.

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2 years ago

A lock has 5 buttons. The lock is opened by pushing two buttons simultaneously and then by pushing one button alone. How many co

Pavel [41]

We first must calculate how many ways 2 oblects can be chosen from 5.

combinations = 5! / 2! * (5-2)!

combinations = 5*4 / 2

combinations = 10

There are 10 ways to choose the 2 buttons and 5 ways to choose the final butto so there are 10 * 5 = 50 different ways.

Source

1728.com/combinat.htm

7 0

2 years ago

Match the following items.

Margarita [4]

Answer:

$1. m\angle ECB=50\\2. m\textrm{ arc BC}=100\\3. m\textrm{ arc CD}=80\\4. m\angle DCF=40$

Step-by-step explanation:

Given:

$\angle DBC=40$ °

From the triangle, using the theorem that center angle by an arc is twice the angle it subtend at the circumference.

$m\textrm{ arc CD}=2\times \angle DBC\\m\textrm{ arc CD}=2\times 40=80$

Also, the diameter of the circle is BD. As per the theorem that says that angle subtended by the diameter at the circumference is always 90°,

$m\angle BCD=90$

From the Δ BCD, which is a right angled triangle,

$m\angle DBC+m\angle BDC=90\textrm{ (right angled triangle)}\\40+m\angle BDC=90\\m\angle BDC=90-40=50$

Now, using the theorem that angle between the tangent and a chord is equal to the angle subtended by the same chord at the circumference.

Here, chords CD and BC subtend angles 40 and 50 at the circumference as shown in the diagram by angles $m\angle DBC\textrm{ and }m\angle BDC$ and EF is a tangent to the circle at point C.

Therefore, $m\angle DCF=m\angle DBC=40\\m\angle ECB=m\angle BDC=50$

Again, using the same theorem as above,

$m\angle DCF=50\\\therefore m\textrm{ arc BC}=2\times m\angle DCF=2\times 50=100$

Hence, all the angles are as follows:

$1. m\angle ECB=50\\2. m\textrm{ arc BC}=100\\3. m\textrm{ arc CD}=80\\4. m\angle DCF=40$

6 0

2 years ago

Read 2 more answers

The thickness of a ﬂange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. Determine the foll

Mrrafil [7]

Answer

given,

thickness of a ﬂange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

X = U[0.95,1.05] 0.95≤ x ≤ 1.05

the cumulative distribution function of flange

F(x) = P{X≤ x}= $\dfrac{x-0.95}{1.05-0.95}$

= $\dfrac{x-0.95}{0.1}$

b) P(X>1.02)= 1 - P(X≤1.02)

= $1- \dfrac{1.02-0.95}{0.1}$

= 0.3

c) The thickness greater than 0.96 exceeded by 90% of the ﬂanges.

d) mean = $\dfrac{0.95+1.05}{2}$

= 1

variance = $\dfrac{(1.05-0.95)^2}{12}$

= 0.000833

4 0

2 years ago