For the last part, you have to find where
attains its maximum over
. We have

so that

with critical points at
such that





So either

or

where
is any integer. We get 8 solutions over the given interval with
from the first set of solutions,
from the set of solutions where
, and
from the set of solutions where
. They are approximately






Good for chelsa. Whats the question here lol. comment it so I can help
Answer:
0.048 is the probability that more than 950 message arrive in one minute.
Step-by-step explanation:
We are given the following information in the question:
The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.
Let X be the number of messages arriving at a multiplexer.
Mean = 15
For poison distribution,
Mean = Variance = 15

From central limit theorem, we have:
where n is the sample size.
Here, n = 1 minute = 60 seconds
P(x > 950)
Calculation the value from standard normal z table, we have,

0.048 is the probability that more than 950 message arrive in one minute.
Answer:
For a = 1.22 there is one solution where y = 1.3
Step-by-step explanation:
Hi there!
Let´s write the system of equations:
a(0.3 - y) + 1.1 +2.4x(y-1.2) = 0
-1.2(x-0.5) = 0
Let´s solve the second equation for x:
-1.2(x-0.5) = 0
x- 0.5 = 0
x = 0.5
Now let´s repalce x = 0.5 and y = 1.3 in the first equation and solve it for a:
a(0.3 - y) + 1.1 +2.4x(y-1.2) = 0
a(0.3 - 1.3) + 1.1 + 2.4(0.5)(1.3 -1.2) = 0
a(-1) + 1.1 + 1.2(0.1) = 0
-a + 1.22 = 0
-a = -1.22
a = 1.22
Let´s check the solution and solve the system of equations with a = 1.22. Let´s solve the first equation for y:
1.22(0.3 - y) + 1.1 +2.4(0.5)(y-1.2) = 0
0.366 - 1.22y + 1.1 + 1.2 y - 1.44 = 0
-0.02y +0.026 = 0
-0.02y = -0.026
y = -0.026 / -0.02
y = 1.3
Then, the answer is correct.
Have a nice day!