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2 years ago

A group of three friends cycle from Llanfyllin to Vyrnwy at 12 km/h.

Mathematics

1 answer:

garik1379 [7]2 years ago

6 0

The average speed for the journey from Llanfyllin to Bala is 14 km/h

Average speed is the ratio of total distance travelled to total time taken. Also, average speed can be given as the average of the different speeds.

Let d₁ represent the distance from Llanfyllin to Vyrnwy and t represent the time taken, since the speed is 12 km/h, hence:

12 = d₁/t

d₁ = 12t

Let d₂ represent the distance from Vyrnwy to bala and t represent the time taken. Since they spent the same time, since the speed is 16 km/h, hence:

16 = d₂/t

d₂ = 16t

Average speed = total distance/total time

Average speed = (d₁ + d₂) / (t + t)

Average speed = (12t + 16t) / 2t

Average speed = 28t / 2t

Average speed = 14 km/h

Hence their average speed for the journey from Llanfyllin to Bala is 14 km/h.

Find out more at: brainly.com/question/23774048

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A company produces remote-controlled helicopters. The company’s profit, in thousands of dollars, as a function of the number of

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Answer:

When 6 helicopters are produced weekly, the company's profit is <u>14 thousand dollars.</u>

Step-by-step explanation:

As per the given statement:

The company profit (in thousands of dollars), as a function of the number of helicopters produced per week can be modeled by a function.

The function that models the scenario is:

$f(h) = -2(h-4)^2 +22$ ......[1]

where

f(h) represents the company's profit

h represents the number of helicopters produced per week.

It is also given that when 1 helicopter is produced per week, the company’s profit is 4 thousand dollars.

Maximum profit for company 22 thousand dollars, occurs when 4 helicopters are produced per week

⇒ $f(1) = 4$ and $f(4) = 22$

we have to find when 6 helicopters are produced weekly, the company profit is;

⇒ h = 6 helicopters

Substitute this value in [1] to solve for f(6);

$f(6) = -2(6-4)^2 +22$

= $-2(2)^2 +22 = -2 \times 4 + 22 = -8 + 22 = 14$

Therefore, the company profit is, 14 thousand dollars.

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2 years ago

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A process engineer is implementing a quality assurance system on a breakfast cereal production line. A new sensor is installed o

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Answer:

0.2%

Step-by-step explanation:

The given parameters are;

The percentage of product within the correct range = 95%

The percentage of the times the sensor reject boxes of incorrect weight = 98%

The percentage of the times the company reject boxes with correct weight = 1%

$\begin{array}{cccc}&P&N&T\\P&TP&0.9&90\\N&FP&9.8&10\end{array}$

We have, FN = 0.9, TN = 9.8, TP = 90 - 0.9 = 89.1, FP = 10 - 9.8 = 0.2

FNR = FN/(FN + TP) = 0.9/(0.9 + 89.1) = 0.01

FPR = 0.2/(0.2 + 9.8) = 0.02

TPR = 89.1/(89.1 + 0.9) = 0.99

TNR = 9.8/(9.8 + 0.2) = 0.98

P(C/A) = TPR × P(C)/((TPR × P(C) + FPR×(1 - P(C)))

Where;

P(C/A) = The probability that a correct weight package is accepted

∴ P(C/A) = 0.99*0.9/(0.99*0.9 + 0.02*0.1) ≈ 0.99776

The probability that a correctly weighed package is rejected, P(C/R), is given as follows;

P(C/R) = 1 - P(C/A)

∴ P(C/R) ≈ 1 - 0.99776 = 0.00224 ≈ 0.2%

The probability that a correctly weighed package is rejected, P(C/R) ≈ 0.2%

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