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Alex
1 year ago
12

it takes max 1.8 hours to walk home from work at a rate of 3.5km/h. how long would it take max to cover the same distance walkin

g at 4.2 km/h
Mathematics
1 answer:
NikAS [45]1 year ago
3 0

Time taken by Max to cover the same distance walking at 4.2 km/h is 1.5 hours

<h3><u>Solution:</u></h3>

Given it takes Max 1.8 hours to walk home from work at a rate of 3.5km/h

We have to find time taken by Max to cover the same distance walking at 4.2 km/h

<em><u>The relation between speed and time is given as:</u></em>

speed = \frac{distance}{time}

<em><u>CASE 1:</u></em>

It takes Max 1.8 hours to walk home from work at a rate of 3.5km/h

Let us first find the distance covered

Time taken = 1.8 hours and speed = 3.5 km/hr

3.5 = \frac{distance}{1.8}\\\\distance = 3.5 \times 1.8 = 6.3

Hence distance covered is 6.3 km

<em><u>Now we have to find the time taken to cover same 6.3 km walking at 4.2 km\hr</u></em>

4.2 = \frac{6.3}{time taken}\\\\time taken = \frac{6.3}{4.2} = 1.5

So time taken by Max to cover the same distance walking at 4.2 km/h is 1.5 hours

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faltersainse [42]

Answer:

<u>(h * h)(10) = 16</u>

Step-by-step explanation:

We should know that: (f*g)(x) = f(x)*g(x)

Given:   h(x) = 6 - x

∴(h * h)(x) = (6-x) (6-x) = (6-x)²

To find (h * h)(10), substitute with x = 10 at (h * h)(x)

∴ (h * h)(10) =  (6-10)² = (-4)² = 16

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Note: if we want to find (hoh)(10)

(hoh)(x) = h[h(x)] = 6 - (6 - x) = 6 - 6 + x = x

∴ (hoh)(10) = 10

8 0
1 year ago
Figures R, S, and T are all scaled copies of one another. Figure S is a scaled copy of R using a scale factor of 3. Figure T is
MakcuM [25]

<em><u>Answer:</u></em>

1/2

1/3

6

1/6

<em><u>Step-by-step explanation:</u></em>

When we are finding the opposite of a scale factor, the scale factor is always the reciprocal. E.g. From S to R, the scale factor is 3, so from R to S, the scale factor is 1/3 so:

1. From T to S, it's the reciprocal of the scale factor (2) so 1/2

2. From S to R, it's the reciprocal of the scale factor (3) so 1/3

3. From R to T, is the from a figure to a figure to a figure so we can multiply the two scale factors (2 and 3) to get 6

4. From T to R, that's the opposite of R to T, so it's the reciprocal of the scale factor from R to T (6) so 1/6

4 0
2 years ago
A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on
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Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

Z_{1-\alpha /2}= Z_{0.95}= 1.645

[10.41±1.645*(\frac{3.71}{\sqrt{28} } )]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0
2 years ago
What is m∠HLK? thanks
Katen [24]
The answer is 80°.

If there is a line segment in a triangle which cuts two sides in half or if there is a line segment between two midpoints of a triangle's sides, that line segment must be parallel to the remaining side.

In this case, point L is the midpoint of FH, and point K is the midpoint of HG. So, LK is parallel to FG.

When a line cuts two parallel lines, there are angle pairs which are equal. In the problem above, the line segment FH cuts KL and GF.

The angles KLH and GFH are what we called "Corresponding Angles" and they are equal.

So if HFG is 80°, HLK must be equal to 80°
3 0
2 years ago
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Answer:

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The budget of 150,000 would allow 150,000/1,200 = 125 pants of design B to be made. The production limit of 120 pants does not use the entire budget.

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2 years ago
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