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Tresset [83]
2 years ago
8

A particular personal trainer works primarily with track and field athletes. She believes that her clients run faster after goin

g through her program for six weeks. How might she test that claim? Multiple Choice A hypothesis test for p1 −p2 . A hypothesis test for μ1−μ2⋅ A matched-pairs hypothesis test for μD. We are unable to conduct a hypothesis test because the samples would not be independent.
Mathematics
1 answer:
masya89 [10]2 years ago
7 0

Answer:

A matched-pairs hypothesis test for μD

Step-by-step explanation:

The trainer wants to compare each athlete's time before the program to the time after the program.  Since we're comparing times for the same athlete, the data is paired, so we should use a matched-pairs test.

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In a basketball tournament, Team A scored 5 fewer than twice as many points as Team B. Team C scored 80 more points than Team B.
nekit [7.7K]

Answer:

(2b - 5) + b + (b + 80) = 983

Step-by-step explanation:

Given that,

Total score of three teams = 983

Since the teams' scores are given in reference to team B's score, let 'b' be the score of team B.

So,

The scores of Team A = (2 * b) - 5

The scores of Team B = b

The scores of Team C = (b + 80)

Thus,

The equation for determining the total points of Team B would be:

(2b - 5) + b + (b + 80) = 983

On solving,

(2b - 5) + b + (b + 80) = 983

⇒ 2b + b + b = 983 + 5 - 80

⇒ 4b = 908

⇒ b = 908 ÷ 4

⇒ b = 227

Team B's score = 227

Team A's score = (2 * 227 - 5)

= 449

Team C's score = 227 + 80

= 307

Total ⇒ 449 + 227 + 307 = 983

Hence proved.

6 0
2 years ago
Sophia was selling tickets at the high school dance. At the end of the evening, she picked up the cash box and noticed a $5 bill
borishaifa [10]
The first thing we will do in this case is to define variables:
 x = number of individual tickets.
 y = number of tickets per couple.
 We have then that the system of equations that represents the problem is:
 10x + 15y = 590
 x + 2y = 68
 Solving the system we have:
 x = 32
 y = 18
 Substituting we have:
 10 (32) + 15 (18) = 590
 320 + 270 = 590
 590 = 590
 Equality is met, therefore the $ 5 bill belongs to the box.
 Answer:
 
the $ 5 bill belong inside the cash box
4 0
2 years ago
he data set gives the number of hours it took each of the 10 students in a cooking class to master a particular technique. {5, 3
sergeinik [125]

The best measure of center tendency for this set of data would be the median. It is the best measurement because the data set has an outlier. The outlier is the 30. So to find the median we first order the data set and then find out if the set is an even or odd set. This set is even so we just chose the middle number. If the set was even, we would add the two center number and divide them by 2.

3, 3, 4, 4, 4, 5, 5, 5, 30

The center tendency = 4

8 0
2 years ago
Read 2 more answers
Add the two expressions. 4.6x−3 and −5.3x+9 Enter your answer, in simplified form, in the box. PLEASE ANSWER FAST THIS IS A BIG
Ivan
To add the two expressions, we can write it as:

4.6x-3 + (-5.3x+9)

We can distribute the plus sign (which means just drop the parenthesis in this case):

4.6x-3-5.3x+9

Now, we can simplify by combining like terms:

-0.7x+6
4 0
2 years ago
Read 2 more answers
On a piece of paper, graph y&lt; x-3. Then determine which answer matches<br> the graph you drew
Aneli [31]

Answer:

The graph is shown below.

Step-by-step explanation:

Given:

The inequality of a line to graph is given as:

y

In order to graph it, we first make the 'inequality' sign to 'equal to' sign. This gives,

y=x-3

Now, we plot this line on a graph. The given line is of the form:

y=mx+b Where, 'm' is the slope and 'b' is the y-intercept.

So, for the line y=x-3, m=1,b=-3

The y-intercept is at (0, -3).

In order to draw the line correctly we find another point. Let the 'y' value be 0.

Now, 0=x-3\\x=3

So, the point is (3, 0).

Now, we mark these points and draw a line passing through these two points.

Now, consider the line inequality y. The 'y' value is less than x-3. So, the solution region will be region below the line and excluding all the points on the line. So, we draw a broken line and shade the region below it.

The graph is shown below.

5 0
2 years ago
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