Answer:
- The amount of time greater than 10.2 hours for this year.
- The
is 0.01358.
Step-by-step explanation:
Given information:
mean, X = 10.2 hours
sample, n = 15
using t distribution
test statistics = 2.822
= 2 x P(
> test statistics)
= 2 x P(
> 2.822)
= 2 x 0.00679
= 0.01358
is less than 0.10 which indicates that the amount of time greater than 10.2 hours for this year.
Answer:
Step-by-step explanation:
Kiesha will have more than 97% of the products working.
Kiesha’s experimental probability is 1/50
When the inventory is 4000 clocks, the prediction is that 3920 clocks will work.
Answer:
Step-by-step explanation:
Correct steps to find the value of 'a' should be,
Braulio's synthetic division should be,
-1 | 1 5 a -3 11
<u> -1 -4 (4 - a) (a - 1) </u>
1 4 (a - 4) (1 - a) (a + 10)
Here remainder is (a + 10).
So (a + 10) = 17 ⇒ a = 7
Braulio Incorrectly found a value of 'a' because he should have used (-1) instead of 1.
Zahra's calculation by remainder theorem should be,
p(x) = x⁴ + 5x³ + ax² - 3x + 11
p(-1) = (-1)⁴ + 5(-1)³ + a(-1)² - 3(-1) + 11
= 1 - 5 + a + 3 + 11
= (a + 10)
Since, remainder of the solution is 17,
(a + 10) = 17 ⇒ a = 7
Zahra incorrectly found the value of 'a' because she incorrectly solved the powers to (-1).
First, you need to put them in order
53kg, 55kg, 61kg, 61kg, 76kg, 91kg, 98kg, 105kg, 120kg
For mean, you add them all up and divide by the amount of numbers (9)
720/9 = 80
For median, you find the middle number (76kg)
For mode, you find the number that appears the most (61kg)
Mean: 80
Median: 76
Mode: 61