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Katena32 [7]
2 years ago
5

The amount of rhubarb in the original recipe is 3 1/2 cups. Using what you know of whole numbers and what you know of fractions,

explain, how you could triple that mixed number.
Mathematics
1 answer:
Alexxx [7]2 years ago
8 0
The easiest way, I think, is to convert the mixed number into an improper fraction, then multiply by 3.
3 1/2 = 7/2
7/2 · 3 = 21/2
now just change the improper fraction back to a mixed number by dividing and putting the remainder into fraction form
21/2 = 10 1/2

You could also multiply the whole number by 3 and the fraction by 3, ending up with 9 3/2, but then have to convert the improper fraction into a mixed number
3/2 = 1 1/2
then add the numbers together
9 + 1 1/2 = 10 1/2
either way works, whatever is easiest for you.  
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Find the quotient. (3.683 × 104) (7.51 × 1012) What is the solution in scientific notation?
olasank [31]

Answer:

B

Step-by-step explanation:

\frac{3.683 \times 10^4}{7.51 \times 10^{12}} \\=\frac{36.83 \times 10^3}{7.51 \times 10^{12}} \\=\frac{36.83}{7.51} \times 10^{3-12}\\ \approx 4.9041 \times 10^{-9}

6 0
1 year ago
Read 2 more answers
Use Euler's formula to derive the identity. (Note that if a, b, c, d are real numbers, a + bi = c + di means that a = c and b =
storchak [24]

Answer with Step-by-step explanation:

We have to prove that

sin 2\theta=2sin\theta cos\theta by using Euler's formula

Euler's formula :e^{i\theta}=cos\theta+isin\theta

e^{i(2\theta)}=(e^{i\theta})^2

By using Euler's identity, we get

cos2\theta+isin2\theta=(cos\theta+isin\theta)^2

cos2\theta+isin2\theta=(cos^2\theta-sin^2\theta+2isin\theta cos\theta)

(a+b)^2=a^2+b^2+2ab, i^2=-1

cos2\theta+isin2\theta=cos2\theta+i(2sin\theta cos\theta)

cos2\theta=cos^2\theta-sin^2\theta

Comparing imaginary part on both sides

Then, we get

sin2\theta=2sin\theta cos\theta

Hence, proved.

8 0
2 years ago
Josh used a standard deck of 52 cards to conduct an experiment. Half of the cards in the deck were red. The other half were blac
geniusboy [140]

Answer: C. He used too few trials for the sample space.


Step-by-step explanation:

Given: Josh used a standard deck of 52 cards to conduct an experiment.

As half of the cards in the deck were red.

If we take sample space= 52 cards

Then probability of getting a red card=\frac{1}{2}

But Josh took 8 cards as sample space which is not enough for the sample space.

therefore, C. is the right answer. "He used too few trials for the sample space."


8 0
1 year ago
Read 2 more answers
Find the area of quadrilateral ABCD. [Hint: the diagonal divides the quadrilateral into two triangles.]
Vadim26 [7]

Answer:

B) 28.53 unit²

Step-by-step explanation:

The diagonal AD divides the quadrilateral in two triangles:

  1. Triangle ABD
  2. Triangle ACD

Area of Quadrilateral will be equal to the sum of Areas of both triangles.

i.e.

Area of ABCD = Area of ABD + Area of ACD

Area of Triangle ABD:

Area of a triangle is given as:

Area = \frac{1}{2} \times base \times height

Base = AB = 2.89

Height = AD = 8.6

Using these values, we get:

Area = \frac{1}{2} \times 2.89 \times 8.6 = 12.43

Thus, Area of Triangle ABD is 12.43 square units

Area of Triangle ACD:

Base = AC = 4.3

Height = CD = 7.58

Using the values in formula of area, we get:

Area = \frac{1}{2} \times 4.3 \times 7.58 = 16.30

Thus, Area of Triangle ACD is 16.30 square units

Area of Quadrilateral ABCD:

The Area of the quadrilateral will be = 12.43 + 16.30 = 28.73 units²

None of the option gives the exact answer, however, option B gives the closest most answer. So I'll go with option B) 28.53 unit²

7 0
2 years ago
The random variable X is normally distributed with mean 82 and standard deviation 7.4. Find the value of q such that P(82 − q &l
mezya [45]
P(82 - q < x < 82 + q) = 0.44
P(x < 82 + q) - P(82 - q) = 0.44
P(z < (82 + q - 82)/7.4 - P(z < (82 - q - 82)/7.4) = 0.44
P(z < q/7.4) - P(z < -q/7.4) = 0.44
P(z < q/7.4) - (1 - P(z < q/7.4) = 0.44
P(z < q/7.4) - 1 + P(z < q/7.4) = 0.44
2P(z < q/7.4) - 1 = 0.44
2P(z < q/7.4) = 1.44
P(z < q/7.4) = 0.72
P(z < q/7.4) = P(z < 0.583)
q/7.4 = 0.583
q = 0.583 x 7.4 = 4.31
8 0
1 year ago
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