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Katena32 [7]
2 years ago
5

The amount of rhubarb in the original recipe is 3 1/2 cups. Using what you know of whole numbers and what you know of fractions,

explain, how you could triple that mixed number.
Mathematics
1 answer:
Alexxx [7]2 years ago
8 0
The easiest way, I think, is to convert the mixed number into an improper fraction, then multiply by 3.
3 1/2 = 7/2
7/2 · 3 = 21/2
now just change the improper fraction back to a mixed number by dividing and putting the remainder into fraction form
21/2 = 10 1/2

You could also multiply the whole number by 3 and the fraction by 3, ending up with 9 3/2, but then have to convert the improper fraction into a mixed number
3/2 = 1 1/2
then add the numbers together
9 + 1 1/2 = 10 1/2
either way works, whatever is easiest for you.  
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Let S(x) denote "x has a good attitude," where the domain is the set of people in the class. Express the negation of the proposi
user100 [1]

Answer:

See below

Step-by-step explanation:

Remember, we have two quantifiers, the existential quantifier ∃, and the universal quantifier ∀. The existential ∃ translates to English as "for some" or "there exists", whereas ∀ means "for all" or "every". We will also use the negation operator ¬.

First, let's write the proposition using quantifiers. "There is someone in this class who does not have a good attitude" translates to "(∃x)(¬S(x))". ∃x means that there exists a person in this class x. ¬S(x) means that x, the person that exists because of the quantifier, does not have a good attitude.

The negation is "¬(∃x)(¬S(x))" or equivalently "(∀x)(S(x))". To negate a proposition using quantifiers, change the quantifier (existential to universal and viceversa) and negate the predicate (in this case we negated ¬S(x)).

In English, "(∀x)(S(x))" means "Every person in this class has a good attitude".

8 0
1 year ago
2.4 puzzle time how can you share five apples with seven friends
Grace [21]

1. The algebraic property of equality that is represented is the multiplication property. The answer is letter P.



2. The algebraic property of equality that is represented is the subtraction property. The answer is letter E.


3. The algebraic property of equality that is represented is the substitution property. The answer is letter M.


4. The algebraic property of equality that is represented is the division property. The answer is letter A.


5. The algebraic property of equality that is represented is the addition property. The answer is letter A.


6. The algebraic property of equality that is represented is the distributive property. The answer is Letter E.


7. The algebraic property of equality that are represented is the transitive property. The answer is letter is E.


8. The algebraic property of equality that are represented is the symmetric property. The answer is Letter A.


9. The algebraic property of equality that are represented is the reflexive property. The answer is letter C.


10. The algebraic property of equality that are represented by is the multiplication property. The answer is letter P.


11. The algebraic property of equality that are represented is the subtraction property. The answer is letter L.



12. The algebraic property of equality that are represented is the reflexive property. The answer is letter S.


13. The algebraic property of equality that are represented is the transitive property. The answer is letter U.


14. The algebraic property of equality that are represented is the symmetric property. The answer is letter K.


The given is 3 5 14 2  4 1 10 11 6 12 8 13 9 7


Plugging in the letters we got for each number, gives us MAKE APPLESAUCE.

6 0
2 years ago
Carlos purchased an antique chair for $15 he later so this year for $27 to an antique dealer what was the percent markup of the
Rama09 [41]
Okay. So, to find the percent change, we have to do change/original. In this case, it would be 12/15, because 15 and 27 are apart by 12. 12/15 is 0.8. Multiply that by 100 and you get 80. There was an 80% markup of the chair sold to the antique dealer.
6 0
2 years ago
Read 2 more answers
A construction explosion has an intensity I of 1.25 x 10–4 W/m2. Find the loudness of the sound in decibels if W/m2. Round to th
bezimeni [28]
We solve this problem by using the decibels formula which is expressed as:

dB = 10 x log (Isig/Iref)

where dB is decibels, Isig is the intensity of the signal and Iref is the intentsity of the softest sound the human ear can hear which has a value of 10^-12.

We solve as follows:
dB = 10 x log (<span>1.25 x 10–4 </span>/ 10^-12 ) = 80.97 decibels

Therefore, the correct answer is option A, 81 decibels.
7 0
1 year ago
Read 2 more answers
Anna made an error in determining the polynomial equation of smallest degree whose roots are -4,-2, -
nalin [4]

Answer:

See explanation

Step-by-step explanation:

Ana started the work nicely by multiplying out factors to get:\

(x+4)(x+2)(2x+1)(x-2)=0

She multiplied (x+2)(x-2) correctly using difference of two squares to get: x^2-4

Unfortunately: She made a mistake in multiplying (x+4)(2x+1) she mistakenly got x^2+9x+4 instead of 2x^2+9x+4. <em>She left out the coefficient of 2.</em>

Therefore the second step should have been:

(x^2-4)(2x^2+9x+4)

The next step will now be:

2x^4+9x^3+4x^2-8x^4-36x-16=0

This simplifies to

2x^4+9x^3-x^4-36x-16=0

8 0
2 years ago
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