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Allisa [31]
2 years ago
7

Megan wants to build a fence around her pool. The pool is 28 feet long by 23 feet wide. The fence is to be 15 feet from the edge

of the pool. How many feet of fencing will she need?

Mathematics
2 answers:
ASHA 777 [7]2 years ago
7 0
23 +30 (15 feet each way) = 53

28 + 30 = 58

58 x 53 = 3074ft
Ber [7]2 years ago
6 0

Answer: 222 feet

Step-by-step explanation:

Given: Megan wants to build a fence around her pool.

The dimensions of the pool is given by :-

28 feet long by 23 feet wide

Since, the fence is to be at distance of 15 feet from the edge of the pool.

Therefore, dimensions of the fence will be :-

(28+15+15) feet long by (23+15+15) feet wide= 58 feet long by 53 feet wide.

Now, the length of the fencing =2(l+w)=2(58+53)=2(111)=222\ ft.

Hence, she will need 222 feet of fencing.

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Point P is at the origin. Then Point P is moved 4 units to the right and 5 units up.
taurus [48]

Answer:

Step-by-step explanation:

The origin (x,y) is (0,0)

If its moved four units right you must add 4 to the x coordinate giving you (4,0)

Then it is moved up by 5, so you must add 5 to the y coordinate giving you

(4,5)

8 0
2 years ago
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An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do
vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107

Then,

P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007

c) In this case, the distribution is B(1200,0.01)

P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366

5 0
2 years ago
Lauren is shopping and finds 6 bracelets, 2 pairs of earrings, and 3 necklaces that she likes. How many ways can Lauren select 4
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Because it does not specify that she has to choose one or two from each category all pieces of jewelry can be treated as choices in a combination set.

the formula for a combination is

C(n,r)= \frac{n!}{r!(n-r)!}

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5 0
2 years ago
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Q: Angelica uses the point (4,3) to represent the location of her house and uses the point (10,8) to represent the location of a
oksian1 [2.3K]

Answer:

The answer to your question is 7.8 mi

Step-by-step explanation:

Data

H (4,3)

G (10, 8)

Process

1.- Use the distance between to points formula to find the distance

        dHG = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2}}

x1 = 4       y1 = 3

x2 = 10    y2 = 8

2.- Substitution

         dHG = \sqrt{(10 - 4)^{2} + (8 - 3)^{2}}

3.- Simplification

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         dHG = \sqrt{36 + 25}

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4.- Result

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