Let numbers of books be 'b' and numbers of CDs be 'c'
We can set up two equations:
Equation [1] ⇒

Equation [2] ⇒

We are solving for the number of books and the number of CDs bought
When we have two equations in terms of two different variables;

and

, that we need to solve, then this becomes a simultaneous equation problem.
First, rearrange Equation [1] to make either

or

the subject:


Then we substitute

into Equation [2]






Now we know the value of

which is

, substitute this value into

we have

Answer:
Numbers of books = 13
Numbers of CDs = 7
If you expand out the brackets you get this,
(4+5i)(a+2i) = 4a + (5a)i + 8i - 10
The -10 comes from 5i * 2i.
Squaring i becomes -1.
Let's group the real stuff together,
and imaginary separately,
(4a - 10) + (5a + 8)i
For this to be purely imaginary,
the real part needs to be zero.
Therefore 4a - 10 = 0
Solve for a.
Answer:
thanks for your help and support you in whatever way you can get back
Answer:
Step-by-step explanation: FF represents the temperature in degrees Fahrenheit is equivalent to CC, the temperature in degrees Celsius.
F=32+1.8CF=32+1.8C
Answer:
To answer your question: Rewrite 81x2 as (9x)2.(9x)2−49Rewrite 49 as 72.(9x)2−72 Both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) where a=9x and b=7.(9x+7)(9x−7)