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2 years ago

ANSWER ASAP PLEASE!!!

1 answer:

6 0

The answer is D. No, it is not a valid inference because his classmates do not make up a random sample of the students in the school.

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Consider the curve y = x − x3. (a) Find the slope of the tangent line to the curve at the point (1, 0). (b) Find an equation of

Katena32 [7]

Answer:

a) mt = -2

b) y=2-2x

Step-by-step explanation:

We have $y=x-x^{3}$ ⇒ $f(x)=x-x^{3}$ and we must find

a) The slope of the tangent line to the curve at the point (1,0)

b) The equation of the tangent line in part (a)

a) $f(x)=x-x^{3}$ with the point (1,0) then f'(x) $=1-3x^{2}$ the slope (mt) in x=1 is

f'(1)= $1-3(1^{2})=1-3=-2$ , m t= -2

b) mt=-2 at the point (1,0), knowing that the pending point model is:

$y-y_{1}=m(x-x_{1})$ , we solve y-0 = -2(x-1) ⇒ y=-2x+2

7 0

2 years ago

Un consejo de estudiantes de un colegio de bachillerato tiene un representante de cada grado. Si cada uno de los miembros del co

Pepsi [2]

Answer:

?????????

Step-by-step explanation:

6 0

2 years ago

Which of the following steps were applied to ABCD to obtain A’B’C’D’?

devlian [24]

Answer:

c- shifted 3 units right and 4 units up

Step-by-step explanation:

In this problem, we have a quadrilateral named as ABCD. Recall that a quadrilateral is a two-dimensional shape having four sides. So, we need to identify what transformation has been performed to get A'B'C'D', which is the same quadrilateral shifted certain units right and up. So take one point, say, B, so how do we need to do to obtain point B'? well, we need to move that point 3 units right and 4 units up, but how can we know this? just count the number of squares you need to move from B to B' horizontally and vertically, which is in fact 3 units right and 4 units up.

6 0

2 years ago

Read 2 more answers

Miguel ran for 850 meters and then walked for 2.75 kilometers.

olga55 [171]

Answer:

1900 meters

Step-by-step explanation:

He ran for 850 meters

Walked for 2.75 kilometers, and that's 2.75 * 1000 meters, which is 2750 meters

The total he walked more than he ran is 2750 - 850 = 1900 meters

4 0

2 years ago

In a game of cornhole, Sasha tossed a bean bag and it landed at the edge of the hole. The hole can be represented by the equatio

Nitella [24]

In the game of cornhole, when Sasha tossed a bean bag to the edge of the hole, in which the equations of the hole and bean bag's path are x² + y² = 5 and y = 0.5x² + 1.5x - 4, respectively, she could have tossed her bean bag to the points (1, -2) or (2, 1).

To find the points in which she could have tossed her bean bag, we need to intersect the two equations of the function as follows.

The equation for the hole

$x^{2} + y^{2} = 5$ (1)