Hello,
<span>We have that:
(4x+10)+(2x-1)=9x-15
</span>We solve the equation:
4x+10+2x-1=9x-15;
6x+9=9x-15;
6x-9x=-15-9;
-3x=-24;
3x=24;
<span>from which
</span>x=24:3=8
<span>Then:
DF=9x-15=(9</span>×8)-15=72-15=57
bye :-)
v=gt,
Initial value when time t=0, v=g*0=0.
t=0 s, v=0 m/s means that object’s initial velocity 0 m/s.
v=gt, and g is a constant g=9.8 m/s². We can write v=9.8*t.
Rate of change 9.8 means the acceleration due to gravity is 9.8 m/s².
Answer: C. The initial value is 0. That means that object’s initial velocity 0 m/s. The rate of change is 9.8. That means the acceleration due to gravity is 9.8 m/s2.
Answer:
11 km/hr.
Step-by-step explanation:
Given information:
Simulated speed = 20/km/h
Time = 15 mins = 1/4 hr = 0.25 hr
Distance Covered as per simulated speed = 
Position of Julian according to the app =
.
Actual distance covered by the bike is

Formula for speed:



Therefore, the average speed of Julian is 11 km/hr.
Answer:
1.5s+2.5p<20
Step-by-step explanation:
Multiply by each kilo and then make sure it adds up to less than 20!
Answer:

In order to find the variance we need to find first the second moment given by:

And replacing we got:

The variance is calculated with this formula:
![Var(X) = E(X^2) -[E(X)]^2 = 0.33 -(0.15)^2 = 0.3075](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%200.33%20-%280.15%29%5E2%20%3D%200.3075)
And the standard deviation is just the square root of the variance and we got:

Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).
Solution to the problem
LEt X the random variable who represent the number of defective transistors. For this case we have the following probability distribution for X
X 0 1 2 3
P(X) 0.92 0.03 0.03 0.02
We can calculate the expected value with the following formula:

And replacing we got:

In order to find the variance we need to find first the second moment given by:

And replacing we got:

The variance is calculated with this formula:
![Var(X) = E(X^2) -[E(X)]^2 = 0.33 -(0.15)^2 = 0.3075](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%200.33%20-%280.15%29%5E2%20%3D%200.3075)
And the standard deviation is just the square root of the variance and we got:
