<span>This intersection produces a line. However, if the angle of the plane is less than the cone's angle, then the intersection produces a point. If the angle of the plane is greater than the angle of the cone, then the intersection is two lines intersecting at the vertex. If the plane intersects at some point other than the vertex, then the intersection is a circle if the plane is perpendicular to the cone's axis. It is an ellipse when the plane's angle is less than the cone's angle. It's a parabola when the planes's angle equals the cone's angle.</span>
Answer:
Option 3 is right.
Step-by-step explanation:
Reference angle of x is obtained by either 180-x, 180+x. or 360-x depending on the posiiton of terminal whether II quadrant or iv quadrant, or iii quadrant, etc.
In whatever way we find reference angles,
cos will remain cos only and sin will remain sin only there may be only changes in sign.
Of all the ordered pairs given, we find that I, II, and Iv there is a switch over form cos to sine and sin to cos. Hence these options cannot be for reference angles.
III option is 
show that both sign and cos changed sign. This is possible only in III quadrant.
ie reference angle of orignal angle t = 180+t
SO this option is right.
Answer:
18 servings
Step-by-step explanation:

Hope this helps!